Answer:
A toy car and with the rest of the money buy big house.
Answer:
The appropriate solution is "1481.76 N".
Explanation:
According to the question,
Mass,
m = 540 kg
Coefficient of static friction,
= 0.28
Now,
The applied force will be:
⇒
By substituting the values, we get
Answer:
first step here is to substitute the 3 of your two equations into the second;
3 Ne^(-Q_v/k(1293)) = Ne^(-Q_v/k(1566))
Since 'N' is a constant, we can remove it from both sides.
We also want to combine our two Q_v values, so we can solve for Q_v, so we should put them both on the same side:
3 = e^(-Q_v/k(1293)) / e^(-Q_v/k(1566))
3 = e^(-Q_v/k(1293) + Q_v/k(1566) ) (index laws)
ln (3) = -Q_v/k(1293) + Q_v/k(1566) (log laws)
ln (3) = -0.13Q_v / k(1566) (addition of fractions)
Q_v = ln (3)* k * 1566 / -0.13 (rearranging the equation)
Now, as long as you know Boltzmann's constant it's just a matter of substituting it for k and plugging everything into a calculator.
Answer:
The increase in pressure of the gas is found to be 15.92 KPa
Explanation:
The additional pressure is equivalent to the pressure exerted by the weight of the mass increased over the area of piston:
Increase in Pressure = ΔP = Weight/Area
ΔP = mg/πr²
m = mass = 25 kg
g = 9.8 m/s²
r = radius of cylinder = 7 cm = 0.07 m
ΔP = (25 kg)(9.8 m/s²)/π(0.07 m)²
ΔP = 245 N/0.01539 m²
<u>ΔP = 15.92 KPa</u>
Therefore, the increase in pressure of gas is 15.92 KPa.