3×6/8 reduce is 3× 3/4= 3/1×3/4=9/4 or 2 1/4
So, pretend this is your x-axis and y-axis:
I
I
(-2,7) • I
I
I • (2, 5)
I
I
I
I
_________________I____________________
I
I
I
TO GET FROM POINT (-2, 7) TO POINT (2, 5), WE MOVE DOWN 2 AND OVER 4, SO THE SLOPE IS -1/2. IF WE FOLLOW THAT SLOPE AND MOVE DOWN 1 AND OVER 2 FROM THE FIRST POINT OF (-2, 7), WE WILL LAND ON A POINT LOCATED AT (0, 6), WHICH WOULD BE THE "Y-INTERCEPT". WE WERE JUST ABLE TO CALCULATE THE SLOPE OF THE LINE AND THEN USE THE SLOPE TO FIND THE INTERCEPT. SO, THE "SLOPE-INTERCEPT" FORM OF THE EQUATION FOR THIS LINE IS:
y = -1/2x + 6
TO RE-WRITE THIS IN STANDARD FORM, WE JUST WANT TO MOVE THE X VARIABLE OVER TO THE LEFT WITH THE Y VARIABLE, SO:
y = -1/2x + 6
+1/2x + 1/2x
1/2x + y = 6 .... and that is your answer!
Answer:
Step-by-step explanation:The following statements are true about exponential functions:
-The domain is all real numbers.
- The input to an exponential function is the exponent.
- The base represents the multiplicative rate of change.
The reason why the other two options are wrong are explained below:
The range of exponential functions is not always includes negative numbers; on the contrary, the range is the set of all positive real numbers.
The graph of an exponential function does not have a horizontal asymptote at x = 0; contrarily, the equation of the horizontal asymptote of the graph of is y = 0, which is the x-axis.
1. 8b+40
2. -36n+16
3. -6y-3
4. 4k+32
5. 3n^2 (squared)
