All categories

3 years ago

The diameter of a circle is 2 yards. What is the circle's radius? d

2 answers:

8 0

The diameter of a circle refers to a straight line passing from side to side through the center connecting to points in the circumference.
In the other hand the radius is a line passing through the center of the circle to the circumference, and it is the half of the measure of the diameter.

On this question is given that the diameter of a circle is 2 yards and it is asked to find the radius.

Radius=1/2diameter
Radius=1/2(2)
Radius=1

The radius of a the circle is 1 yard.

Natalka [10]3 years ago

6 0

The circle's radius is 1 yard. You take half of the diameter to get this value.

You might be interested in

What is the nth term of the sequence 19, 15.5, 12, 8.5, 5

Nikitich [7]

Answer: 6.5 and 6 is the 9th term

Step-by-step explanation:

3 0

3 years ago

Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=

luda_lava [24]

Let $f(x) = x^3 - 2x - 2$ . Then differentiating, we get

$f'(x) = 3x^2 - 2$

We approximate $f(x)$ at $x_1=2$ with the tangent line,

$f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18$

The $x$ -intercept for this approximation will be our next approximation for the root,

$10x - 18 = 0 \implies x_2 = \dfrac95$

Repeat this process. Approximate $f(x)$ at $x_2 = \frac95$ .

$f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}$

Then

$\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}$

Once more. Approximate $f(x)$ at $x_3$ .

$f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}$

Then

$\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}$

Compare this to the actual root of $f(x)$ , which is approximately 1.769292354, matching up to the first 5 digits after the decimal place.

4 0

2 years ago

If a plate is moving 3.3 cm/yr, what distance [in kilometers (km)] will the plate move in 1 million years?

sasho [114]

$\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}$

3.3cm = 0.000033km (divide by 100,000.

So, 0.000033km/yr.

0.000033 × 1,000,000

=33km

Thanks
Hope it helps

3 0

3 years ago

SOLVE THIS EXTREMELY IMPORTANT EQUATION

finlep [7]

Answer:

Option B; EF = ( About ) 4.47 units, Perimeter of Δ EFG = ( About ) 12.94 units

Step-by-step explanation:

If we were to consider the height of this triangle EFG, it would be 4 units of length, supposedly splitting base GF into two ≅ parts, each 2 units of length. First let us name the point drawn to base GF ⇒ point H, so that the height of Δ EFG ⇒ EH. Now as EH splits GF into two ≅ parts, by Converse to Coincidence Theorem, Δ EFG ⇒ Isosceles Δ;

EH and FH are legs of a right triangle EFH, so that Pythagorean Theorem can be applied to solve for the length of EF and EG, knowing that as Δ EFG ⇒ Isosceles Δ, EF ≅ EG;

( EH )^2 + ( FH )^2 = ( EF )^2,

( 4 )^2 + ( 2 )^2 = ( EF )^2 ⇒ take square of 4 & 2,

16 + 4 = ( EF )^2 ⇒ combine like terms,

( EF )^2 = 20 ⇒ take square root on either side to solve for EF,

EF = √ 20 = ( About ) 4.47 units = EG,

Perimeter of Δ EFG = EF + GF + EG = 4.47 + 4 + 4.47 = ( About ) 12.94 units,

Solution; Option B

6 0

3 years ago

PLEASE THINS IS DUE BY 1 P.M TODAY. PLEASE HELP ME

zaharov [31]

$6 {x}^{2} {y}^{2} (y + 3xy + 6x)$

6 0

3 years ago