Answer:
The domain of the function is all real values of x, except
and 
Step-by-step explanation:
We are given the following function:

It's a fraction, so the domain is all the real values except those in which the denominator is 0.
Denominator:
Quadratic equation with 
Using bhaskara, the denominator is 0 for these following values of x:



The domain of the function is all real values of x, except
and 
Answer:
Step-by-step explanation:
Find the roots of x^2-25=0 by solving for x.
Add 25 to both sides
x^2=25
Square root both sides
x=-5
x=5
Answer:
A
Step-by-step explanation:
a geometric sequence is where we multiply a factor from element to element.
a1 = $900
a2 = 981 = a1 × f = 900 ×
a3 = 1069.29 = a2 × f = a1 × f × f = s1 × f²

so, now let's try and get f.
remember, 981 = 900 × f
f = 981/900 = 109/100 = 1.09
just to control, we check for s3 :
900 × (1.09)² = 900 × 1.1881 = 1069.29
correct.
so,
a13 = 900 × (1.09)¹² = 2,531.398304
s13 is then the sum of all a1, ..., a13
there is a nice formula for sums of finite sequences
s13 = 900 × (1-f¹³) / (1-f) = 900×(1-(1.09)¹³) / (1-1.09) =
= 900×(1-3.065804612) / (-0.09) =
= 900×(-2.065804612) / (-0.09) = 20,658.04612
.
Answer:
Option b
Step-by-step explanation:
Given that For a particular course, the pass rate for the 16-week format is 59%. A team of faculty examine student data from 40 randomly selected accelerated classes and determine that the pass rate is 78%.
we have to find whether taking a class in a short-term format (8 weeks instead of 16 weeks) increase a student’s likelihood of passing the course
Since pass rate for 16 weeks is 59% we check whether for 8 weeks is more than this.
So correct null and alternative hypotheses for this research question
would be:
b.H0: p = 0.59; Ha: p > 0.59
Option b is right.