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Vladimir79 [104]
3 years ago
7

I need help with this slope problem please!

Mathematics
1 answer:
Flura [38]3 years ago
3 0

Answer:

m= 0/-2

Step-by-step explanation:

<h3>              y2-y1         6-6           0</h3><h3>    m=   ----------- = ----------- = -------</h3><h3>              x2-x1        -4+2         -2</h3>
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6. In the figure below, measure of angle 1 = 3x + 5, measure of angle 2 = 5x - 18, and measure of angle 3 = 7x-2
Lesechka [4]
See photo for solution and mark me as brainliest if i helped :)

A: although it seems like they are forming a 90º angle, they actually add up to a 89 º angle and therefore are not complementary

B: see photo

4 0
3 years ago
What is the slope given the following two points (2,-4) and (1, 5)?
VMariaS [17]

Answer:

-9/1

Step-by-step explanation:

4 0
3 years ago
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A line that passes through (5, 1) and has a slope of ?
aalyn [17]
A line that passes through (5, 1) can have ANY slope and ANY y-intercept. There are an infinite number of different lines that pass through that point.
5 0
3 years ago
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Write an equation in standard form for each line.
LenaWriter [7]

The standard form: Ax + By = C.

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}


7. We have the points (4, -7) and (2, -3). Substitute:

m=\dfrac{-3-(-7)}{2-4}=\dfrac{4}{-2}=-2\\\\y-(-7)=-2(x-4)\qquad|\text{use distributive property}\\\\y+7=(-2)(x)+(-2)(-4)\\\\y+7=-2x+8\qquad|-7\\\\y=-2x+1\qquad|+2x\\\\\boxed{2x+y=1}

8. We have the points (1, 5) and (-10, -6). Substitute:

m=\dfrac{-6-5}{-10-1}=\dfrac{-11}{-11}=1\\\\y-5=1(x-1)\\\\y-5=x-1\qquad|+5\\\\y=x+4\qquad|-x\\\\-x+y=4\qquad|\text{change the signs}\\\\\boxed{x-y=-4}


7 0
3 years ago
HURRY!!!<br> a<br> Undefined<br> b<br> Negative<br> c<br> Zero<br> d<br> Positive
Fiesta28 [93]

Answer:

A, undefined

Step-by-step explanation:

The general rule is that vertical lines are undefined slope, because there's literally no change in x values. The vertical line test also fails, meaning there is no slope. Horizontal lines have a slope of 0, while vertical lines don't own any numbers that are important except for x-axis numbers.

If you do y2-y1 over x2-x1, you literally get 1/0 which is nothing. 0/1 = 0, but 1/0 is nothing.

Hope this helps!

6 0
3 years ago
Read 2 more answers
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