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saveliy_v [14]
3 years ago
13

A sinusoidal carrier wave has an amplitude of 5 volts, a frequency of 1MHz, and zero phase angle. Select the correct carrier wav

e equation.
a. c(t) = 1E6 cos(2π*5*t)
b. c(t) = 5 cos(2π*1E6*t)
c. c(t) = 5 cos(π*2E6*t)
d. either b or c
Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0

Answer:

The correct answer is b.

Step-by-step explanation:

The wave equation is given generally as:

c(x, t) = Acos(kx - wt)

Where A = amplitude

k = wave number

w = angular frequency.

x = horizontal distance moves by the wave.

t = time

The options show to us that the wave depends only on t and not (x, t).

Hence, the wave equation becomes:

c(t) = Acos(wt)

Given that:

A = 5 V

f = 1 * 10⁶ Hz

Angular Frequency, w, is given as:

w = 2πf

w = 2 * π * 1 * 10⁶ Hz

w = 2π(1 * 10⁶)

The wave equation becomes:

c(t) = 5cos(2*π*1*10⁶)

The correct answer is b.

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Answer:

$39.96

Step-by-step explanation:

Since it is 20% off, we would multiply by .8, as we subtract the .2 (20%) off of the price.

$49.95 x 0.8 = $39.96

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Phillip claimed that the expression − p + 5 + p is positive for any value of p. Determine whether Phillip’s statement is always
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Answer:

always true.

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3 years ago
Find the slope intercept form of the equation of the line that’s has the given properties (1 , 3) m=1/4
Helga [31]

Answer:

y = 1/4x + 11/4

Step-by-step explanation:

Given the slope, m = 1/4, and the point, (1, 3):

We can substitute these values into the slope-intercept form, y = mx + b, in order to solve for the y-intercept.  

The y-coordinate (b) of the point, (0, <em>b </em>) is the <u>y-intercept </u>of the line where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0.

y = mx + b

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3 = 1/4 + b

Subtract 1/4 from both sides:

3 - 1/4 = 1/4 - 1/4 + b

11/4 = b

The y-coordinate, b, of the y-intercept is 11/4.

Therefore, the slope-intercept form is: y = 1/4x + 11/4

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