To have infinitely many solutions they must describe the same line. So any multiple or fraction of the reference line would indeed describe the same line, and thus "intersect" at each and every of an infinite number of points.
2(x+y=4)
2x+2y=8 (is the same line as x+y=4)
Answer:
x= 4 y= 7 z= -6
Step-by-step explanation:
solve for one and you get them all
First, I got rid of the z by multiplying common factors (multiplied z by 2) and added equations 2 and 3 together after multiplying by 2
4x - 3y - 2z = 7
-10x+10y+2z= 18
-6x+7y= 25
Then multiplied z by -3 (to get rid of the z) with the original equation 3
3x - 2y + 3z = -20
15x-15y-3z= -27
18x-17y= -47
Next find common thing between the 2 equations we got and multiply it by that and combine (we can multiply first equation by 3 to get rid of the x and solve for y)
-18x+21y= 75
18x-17y= -47
y=7
Work backwards, substitute 7 into the above equation, you get x= 4 and then same for z to get z= -6
Checking the <span>discontinuity at point -4
from the left f(-4) = 4
from the right f(-4) = (-4+2)² = (-2)² = 4
∴ The function is continues at -4
</span>
<span>Checking the <span>discontinuity at point -2
from the left f(-2) = </span></span><span><span>(-2+2)² = 0
</span>from the right f(-2) = -(1/2)*(-2)+1 = 2
∴ The function is jump discontinues at -2
</span>
<span>Checking the <span>discontinuity at point 4
from the left f(4) = </span></span><span><span>-(1/2)*4+1 = -1
</span>from the right f(4) = -1
but there no equality in the equation so,
</span><span>∴ The function is discontinues at 4
The correct choice is the second
point </span>discontinuity at x = 4 and jump <span>discontinuity at x = -2</span>
