1. distribute a 1 to the 12 and 8a
2. you'll get 15+ 12 +8a
3. add the like terms(15 and 12)
4. your final answer will be 27+8a
Answer:
1:
<A=½(arcJL)=½(70+120)=35+60=95°
[inscribed angle is half of central angle]
2:
<W=½arcVX=½(130)=65°
[inscribed angle is half of central angle]
3.
<E=½(arcDC)=½(90)=45°
[inscribed angle is half of central angle]
4.
<R=½(arcXZ)=½(110+62)=86°
[inscribed angle is half of central angle]
5.
<B=½(arc DC)=½×104°=52°
[inscribed angle is half of central angle]
6.
<K=90°
[inscribed angle in a diameter is complementary]
<K+<J+<L=180°(sum of interior angle of a triangle]
<L=180°-90°-53°=37°
again
arc JK=2×<L=2×37=74°
22% = 22/100
22/100 * 14.50 = 3.19 (this is the amount discounted off original price)
14.50 - 3.19 = $11.31
Answer: 59
Step-by-step explanation:
-7 (-6) + 17 (multiply -7 and -6)
= 42+17 (simplify)
=59
A(-7,-4) B(-2,0)
√[(x'-x)^2+(y'-y)^2]
√(-2-(-7)^2+(0-(-4)^2
√(5^2)+(4^2)
√25+16
√41
the distance is approximately 6.4 units