Answer: the distance of the base of the house to the foot of the ladder is 6.84 feet
Step-by-step explanation:
The scenario is shown in the attached photo.
Right angle triangle ABC is formed when the ladder leans against the wall of the house.
AC = the height of the ladder
AB = x feet = distance of the base of the house to the foot of the ladder
BC is the wall of the building.
To determine x, we will apply trigonometric ratio
Cos # = adjacent/hypotenuse
Where
# = 70 degrees
Hypotenuse = 20
Adjacent = x
Cos 70 = x/20
x = 20cos70
x = 20 × 0.3420
x = 6.84 feets
The value of three in 6,300 is 3,000 because it is in the thousands place. The three in 530 is in the hundreds place making the value of three 300. Hope that this helps you :D
First picture)
I: 5x+2y=-4
II: -3x+2y=12
add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2
insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3
(-2,3)
question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs
insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults
insert adults into II:
33-8=childs
25=childs
so it's the last option
question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6
so it's the last option
question 8)
I: x+y=12
II: x-y=6
subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3
insert y into I:
x+3=12
x=9
(9,3)
question 9)
I: x+y=6
II: x=y+5
if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6
which is the second option :)
Answer:
what?
Step-by-step explanation:
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