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3 years ago

8

Carlos is adding the mixed numbers 1 1/5 and 2 1/8 by changing each number into an improper fraction. Which pair of improper fra

ctions should Carlos use?

1 answer:

irga5000 [103]3 years ago

3 0

Answer

6/5 and 17/8

Step-by-step explanation:

1 1/5 = 6/5

1= 5/5 + 1/5 = 6/5

2 1/8 = 17/8

2 = 16/8 + 1/8 = 17/8

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3 years ago

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katen-ka-za [31]

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Step-by-step explanation:

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2 years ago

Melissa owns a catering company . For lunch and dinner parties , she serves appetizers before each meal. The number of appetizer

german

Answer:

44

Step-by-step explanation:

Lunch = 3 appetizers per guest

If there are 22 guests: 22 × 3 = 66 appetizers served

Dinner = 5 appetizers per guest

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2 years ago

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Shkiper50 [21]

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3 years ago

Read 2 more answers

A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat

konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles

First, we need to find b:

$a^{2} + b^{2} = h^{2}$ (1)

$b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles$

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

$\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})$

$2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:

$0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

$\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h$

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0

2 years ago