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3 years ago

10,500 J of GPE, weight 539 N, how tall is the hill you are sitting on?

Physics

1 answer:

maks197457 [2]3 years ago

6 0

Answer:

19.48 m

Explanation:

Gravitational potential energy = mgh

Current weight = 539 N

Weight = mg = 539 N

Mass x Acceleration = 539 N

Mass x 9.81 = 539

Mass = 54.94 kg

Gravitational potential energy = mgh = 10500 J

54.94 x 9.81 x h = 10500

h = 19.48 m

Height of sitting = 19.48 m

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An electron and a proton each have a thermal kinetic energy of 3kBT/2. Calculate the de Broglie wavelength of each particle at a

IgorLugansk [536]

Answer:

The de Broglie wavelength of electron βe = 2.443422 × 10⁻⁹ m

The de Broglie wavelength of proton βp = 5.70 × 10⁻¹¹ m

Explanation:

Thermal kinetic energy of electron or proton = KE

∴ KE = 3kbT/2

given that; kb = 1.38 x 10⁻²³ J/K , T = 1950 K

so we substitute

KE = ( 3 × 1.38 x 10⁻²³ × 1950 ) / 2

kE = 4.0365 × 10⁻²⁰ ( is the kinetic energy for both electron and proton at temperature T )

Now we know that

mass of electron M'e = 9.109 × 10⁻³¹

mass of proton M'p = 1.6726 × 10⁻²⁷

We also know that

KE = p₂ / 2m

from the equation, p = √ (2mKE)

{ p is momentum, m is mass }

de Broglie wavelength = β

so β = h / p = h / √ (2mKE)

h = Planck's constant = 6.626 × 10⁻³⁴

∴ βe = h / √ (2m'e × KE)

βe = 6.626 × 10⁻³⁴ / √ (2 × 9.109 × 10⁻³¹ × 4.0365 × 10⁻²⁰ )

βe = 6.626 × 10⁻³⁴ / √ 7.3536957 × 10⁻⁵⁰

βe = 6.626 × 10⁻³⁴ / 2.71176984642871 × 10⁻²⁵

βe = 2.443422 × 10⁻⁹ m

βp = h / √ (2m'p ×KE)

βp = 6.626 × 10⁻³⁴ / √ (2 × 1.6726 × 10⁻²⁷ × 4.0365 × 10⁻²⁰ )

βp = 6.626 × 10⁻³⁴ / √ 1.35028998 × 10⁻⁴⁶

βp = 6.626 × 10⁻³⁴ / 1.16201978468527 × 10⁻²³

βp = 5.702140 × 10⁻¹¹ m

3 0

3 years ago

A trolley of mass 4 kg moves with a velocity of 0.5 meter per second It colides with a stationary trolley of mass 3 kg. If the t

Luda [366]

Answer:

Approximately $0.29\; {\rm m \cdot s^{-1}}$ .

Explanation:

Make use of the fact that total momentum is conserved in collisions.

The momentum of an object of mass $m$ and velocity $v$ is $p = m\, v$ .

The momentum of the two trolleys before the collision would be:

$4\; {\rm kg} \times 0.5\; {\rm m \cdot s^{-1}} = 2\; {\rm kg \cdot m \cdot s^{-1}}$ .
$3\; {\rm kg} \times 0\; {\rm m\cdot s^{-1}} = 0\; {\rm kg \cdot m \cdot s^{-1}}$ .

Thus, the total momentum of the two trolleys right before the collision would be $2\; {\rm kg \cdot m \cdot s^{-1}}$ .

Since the two trolleys are stuck to one another after the collision, they could modelled as one big trolley of mass $m = 3\; {\rm kg} + 4\; {\rm kg} = 7\; {\rm kg}$ .

The momentum of the two trolleys, combined, is conserved during the collision. Thus, the total momentum of the new trolley of mass $m = 7\; {\rm kg}$ would continue to be $v = 2\; {\rm kg \cdot m \cdot s^{-1}}$ shortly after the collision.

Rearrange the equation $p = m\, v$ to find the velocity of the two trolleys combined:

$\begin{aligned}v &= \frac{p}{m} \\ &= \frac{2\; {\rm kg \cdot m \cdot s^{-1}}}{7\; {\rm kg}} \\ &\approx 0.29\; {\rm m \cdot s^{-1}}\end{aligned}$ .

6 0

2 years ago

2. While standing near a bus stop, a student hears a distant horn beeping. The frequency emitted by the horn is 440 Hz. The bus

jarptica [38.1K]

Given Information:

Frequency of horn = f₀ = 440 Hz

Speed of sound = v = 330 m/s

Speed of bus = v₀ = 20 m/s

Answer:

Case 1. When the bus is crossing the student = 440 Hz

Case 2. When the bus is approaching the student = 414.9 Hz

Case 3. When the bus is moving away from the student = 468.4 Hz

Explanation:

There are 3 cases in this scenario:

Case 1. When the bus is crossing the student

Case 2. When the bus is approaching the student

Case 3. When the bus is moving away from the student

Let us explore each case:

Case 1. When the bus is crossing the student:

Student will hear the same frequency emitted by the horn that is 440 Hz.

f = 440 Hz

Case 2. When the bus is approaching the student

f = f₀ ( v / v+v₀ )

f = 440 ( 330/ 330+20 )

f = 440 ( 330/ 350 )

f = 440 ( 0.943 )

f = 414.9 Hz

Case 3. When the bus is moving away from the student

f = f₀ ( v / v+v₀ )

f = 440 ( 330/ 330-20 )

f = 440 ( 330/ 310 )

f = 440 ( 1.0645 )

f = 468.4 Hz

6 0

3 years ago

Match the layer of Earth with its characteristic.

mote1985 [20]

Answer:

Explanation:

The Asthenosphere -- drives the movement in the plates

It is a weak and flexible part of the upper mantle of the planet Earth.

It is located below the lithosphere. The depth of it is between 200 and 80 kilometers below the surface. It is usually solid but in some regions it is fluid. The temperature dictates the thickness of the Asthenosphere.

The Core -- the hottest layer of the Earth.

The inner Core of the Earth is a layer that's located in the core of it. By definition, it is a rock-hard ball that has the radius of 1,220 kilometers, making it 20% of the Earth's radius and 70% of the Moon's radius. The samples are not discovered. It is believed that it has the composition of iron-nickel infusion along with other elements. The temperature is appx. 5430 °C, which is similar to the temperature of the surface of the Sun.

Mesosphere -- contains the lower mantle

By definition, it comes from the Greek word mesos, which means '' middle ''.

It is the third layer of the Earth. It is located above the stratosphere and below the thermosphere. The higher the altitude, the lower the temperature. It ends in the coldest part of the Earth, Mesopause. And it begins at the Stratosphere.

Lithosphere -- contains the tectonic plates

By the definition, it is also a word that came from the Greek language. It comes from the word '' lithos '' which means '' rocky ''.

It is a hard, outer part of the Earth.

On the planet Earth, it is made out of the crust of the upper mantle. The rocks from the Lithosphere are elastic.

They are two types of Lithosphere -- the oceanic Lithosphere and Continental Lithosphere.

6 0

3 years ago

Read 2 more answers

Which is the best estimate for the mass of a typical lineman on a high school football team

fgiga [73]

We have that the best estimate for the mass of a typical lineman on a high school football team is

$100,000 g=100kg$