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Vera_Pavlovna [14]
3 years ago
12

A sound wave moving through the air causes particles in the air to move. If air particles are moving, why doesn’t this motion cr

eate a breeze?
Physics
1 answer:
mylen [45]3 years ago
3 0

Answer:

The motion of air particle caused by sound wave is vibrational and cannot create breeze because breeze involves translational motion (permanent displacement) of the air particles.

Explanation:

This sound wave results from the back and forth vibration of the particles of air through which the sound wave is moving. The sound wave causes disturbance within the particles of air by transfering energy from one particle to the adjacent particles of air without causing permanent displacement of the particles of air. The motion between these particles of air caused by sound wave is vibrational, while breeze involves displacement of particles of air through translational motion. Hence, breeze is a moving mass of air.

Thus, the motion of air particle caused by sound wave is vibrational and cannot create breeze because breeze involves translational motion (permanent displacement) of the air particles.

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Astronomers discover a bright X-ray source in the Milky Way. They see no counterpart in the optical bands, but it has another st
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a. a black hole

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The law of universal gravitation states that any two objects in the universe, without exception,
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3 years ago
A 25.0-g sample of copper at 363 K is placed in I 00.0 g of water at 293 K. The copper and water quickly come to the sa me tempe
Simora [160]

Answer:

Final temperature is 295K

Explanation:

Where the sample of copper is placed in the water, the heat transferred from the copper is equal that the heat absorbed by the water.

The heat transferred from the copper is:

C×\frac{1mol}{63,546g}×mass×ΔT

Where C is molar heat capacity of copper (24,5J/molK)

Mass is 25,0g

And ΔT is final temperature - initial temperature (X-363K)

Also, the heat absorbed by the water is:

-C×\frac{1mol}{18,02g}×mass×ΔT

Where C is molar heat capacity of water (75,2J/molK)

Mass is 100,0g

And ΔT is final temperature - initial temperature (X-293K)

As heat transferred is equal to heat absorbed:

24,5J/molK×\frac{1mol}{63,546g}×25,0g×(X-363K) = -75,2J/molK×\frac{1mol}{18,02g}×100,0g× (X-293K)

9,64X J/K - 3499J = - 417X J/K + 122273J

426,64X J/K = 125772 J

<em>X = 295K</em>

<em></em>

Final temperature is 295K

I hope it helps!

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3 years ago
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