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3 years ago

Why does it take more time for a larger sample of water to freeze?

2 answers:

3 0

Answer:The greater the amount of water that there is it will take longer for the water to freeze because more heat has to be dissipated into the environment

Explanation:

exis [7]3 years ago

3 0

Answer:

The greater the mass of water, the more heat has to be dissipated into the environment and the longer it will take to freeze. The greater the surface area of the water, the faster the water will lose its heat and freeze.

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Astronomers study objects as large as galaxies. Chemists study objects that can be as small as an atom. Which of the following i

Inessa [10]

Answer:

A. both fields use the same technology

Explanation:

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3 years ago

Read 2 more answers

How to determine the center of gravity of a lamina

goldenfox [79]

Take a lamina with three holes near the periphery of the lamina, now suspend the lamina through them, one by one. Draw a line of equilibrium for each suspension point. The point of intersection of these three lines would be the centre of gravity.

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2 years ago

inna [77]

Answer:

5g/cm

Explanation:

denisty=mass/volume

100/20

5g/cm

8 0

3 years ago

A physics teacher performing an outdoor demonstration suddenly falls from rest off a high cliff and simultaneously shouts "Help.

uranmaximum [27]

Answer:

532.0725 m

102.17270893 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² = g

H = Height of cliff

Distance traveled in 3 seconds

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 3^2\\\Rightarrow s=44.145\ m$

Distance traveled by sound = 2H-44.145 m

$2H-44.145=ut+\dfrac{1}{2}at^2\\\Rightarrow 2H-44.145=340\times 3\\\Rightarrow H=\dfrac{340\times 3+44.145}{2}\\\Rightarrow H=532.0725\ m$

The height of the cliff is 532.0725 m

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 532.0725+0^2}\\\Rightarrow v=102.17270893\ m/s$

Her speed just before she hits the ground is 102.17270893 m/s

5 0

3 years ago

What is the acceleration of a car initially traveling at -5m/s and<br> reaching -22m/s in 3s.

lozanna [386]

Answer:

$a=-5.67\ m/s^2$

Explanation:

Given that,

Initial velocity, u = -5 m/s

Final velocity, v = -22 m/s

Time, t = 3s

We need to find the acceleration of the car. The formula of it is given by :

Acceleration,

$a=\dfrac{v-u}{t}\\\\a=\dfrac{(-22)-(-5)}{3}\\\\a=-5.67\ m/s^2$

So, the acceleration of the car is $-5.67\ m/s^2$ .

4 0

3 years ago