=0.5 x40
<span>= (calculate it) </span>
<span>2. F= -.45 x 41 </span>
<span>= </span>
<span>3. F=20 x 12 </span>
<span>= </span>
<span>4. F=50 x 30 </span>
<span>= </span>
<span>I believe you can go on from here, remember its easy </span>
<span>for the last 2 just rearange the formual </span>
<span>for 9 it will be a=F/m and 10. m=f/a </span>
Answer:
The answer is 100% A THE ANSWER IS A!!!!
Explanation:
i have a 100 in all of my classes including science
Answer:
C) T
Explanation:
= Mass attached to an ideal spring
= Amplitude of the motion
= Time period of oscillation
= Spring constant of the spring
= Amplitude of the motion
Time period of oscillation of the mass attached to the spring is given as
So we see that the time period does not depend on the amplitude. hence the period of oscillation remains the same.
The difference in frequency of the two signals is 
.
The given parameters;
- <em>frequency of the 13 C signal = 201.16 MHz</em>
The energy of the 13 C signal located at 20 ppm is calculated as follows;
The energy of the 13 C signal located at 179 ppm is calculated as follows;
The difference in frequency of the two signals is calculated as follows;
Thus, the difference in frequency of the two signals is .
Learn more here:brainly.com/question/14016376
Answer:
the answers the correct one is cη
Explanation:
In this simple pendulum experiment the student observes a significant change in time between each period. This occurs since an approximation used is that the sine of the angle is small, so
sin θ = θ
with this approach the equation will be surveyed
d² θ / dt² = - g / L sin θ
It is reduced to
d² θ / dt² = - g / L θ
in which the time for each oscillation is constant, for this approximation the angle must be less than 10º so that the difference between the sine and the angles is less than 1%
The angle is related to the height of the pendulum
sin θ = h / L
h = L sin θ.
Therefore the student must be careful that the height is small.
When reviewing the answers the correct one is cη
