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insens350 [35]
4 years ago
11

Which choices are correct based on the images provided

Chemistry
2 answers:
Darya [45]4 years ago
7 0

Answer: each atom and the shared electrons,

valence electrons

Explanation: A covalent compound is defined as the compound which is formed from the sharing of electrons between the element that are combining together.

These compounds are most likely to be formed when two non-metals combine together. For Examples: F_2

Flourine is an element with tomic number 9 and has 7 valence electrons

F:9:1s^22s^22p^5

Thus for formation of  a F_2 molecule, they share their valence electrons and attain stable configuration.

Lina20 [59]4 years ago
3 0

In a covalent bond, two atoms are held together by the attraction between each atom and the shared electrons. the number of covalent bonds that an atom can form depends on the number of valence electrons in the atom.


hope dis helped u daddy

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Answer:

The solution to the question is as follows

(a) The rate of ammonia formation = 0.061 M/s

(b) the rate of N₂ consumption = 0.0303 M/s

Explanation:

(a) To solve the question we note that the reaction consists of one mole of N₂ combining with three moles of H₂ to form 2 moles of NH₃

N₂(g) + 3H₂(g) → 2NH₃(g)

The rate of reaction of molecular hydrogen = 0.091 M/s, hence we have

3 moles of H₂ reacts to form 2 moles of NH₃, therefore

0.091 M of H₂ will react to form 2/3 × 0.091 M or 0.061 M of NH₃

Hence the rate of ammonia formation is 0.061 M/s

(b) From the reaction equation we have 3 moles of H₂ and one mole of N₂ being consumed at the same time hence

0.091 M of H₂ is consumed simultaneously with 1/3 × 0.091 M or 0.0303 M of N₂

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6 0
3 years ago
Sugar is used to fill a box that has a volume of 200 cm3. The sugar weighs 316 grams. What is the density of sugar? (Ignore the
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<u>Answer:</u> The density of sugar is 1.58g/cm^3

<u>Explanation:</u>

To calculate the density of a substance, we use the equation:

Density=\frac{Mass}{Volume}

We are given:

Mass of sugar = 316 g

Volume of box = 200cm^3

Putting values in above equation, we get:

\text{Density of sugar}=\frac{316g}{200cm^3}\\\\\text{Density of sugar}=1.58g/cm^3

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Answer: The enthalpy change during this reaction is 77505.56 J.

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Given: T_{1} = 14^{o}C,         T_{2} = 87^{o}C

Mass = 254 g,       Specific heat = 4.18 J/g^{o}C

Formula used to calculate the enthalpy change is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = enthalpy change

m = mass of substance

C = specific heat capacity

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T_{2} = final temperature

Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 254 g \times 4.18 J/g^{o}C \times (87 - 14)^{o}C\\= 77505.56 J

Thus, we can conclude that the enthalpy change during this reaction is 77505.56 J.

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