Answer:
The solution to the question is as follows
(a) The rate of ammonia formation = 0.061 M/s
(b) the rate of N₂ consumption = 0.0303 M/s
Explanation:
(a) To solve the question we note that the reaction consists of one mole of N₂ combining with three moles of H₂ to form 2 moles of NH₃
N₂(g) + 3H₂(g) → 2NH₃(g)
The rate of reaction of molecular hydrogen = 0.091 M/s, hence we have
3 moles of H₂ reacts to form 2 moles of NH₃, therefore
0.091 M of H₂ will react to form 2/3 × 0.091 M or 0.061 M of NH₃
Hence the rate of ammonia formation is 0.061 M/s
(b) From the reaction equation we have 3 moles of H₂ and one mole of N₂ being consumed at the same time hence
0.091 M of H₂ is consumed simultaneously with 1/3 × 0.091 M or 0.0303 M of N₂
Therefore the rate of consumption of N₂ = 0.0303 M/s
<u>Answer:</u> The density of sugar is 
<u>Explanation:</u>
To calculate the density of a substance, we use the equation:

We are given:
Mass of sugar = 316 g
Volume of box = 
Putting values in above equation, we get:

Hence, the density of sugar is 
Answer: The enthalpy change during this reaction is 77505.56 J.
Explanation:
Given:
, 
Mass = 254 g, Specific heat = 
Formula used to calculate the enthalpy change is as follows.

where,
q = enthalpy change
m = mass of substance
C = specific heat capacity
= initial temperature
= final temperature
Substitute the values into above formula as follows.

Thus, we can conclude that the enthalpy change during this reaction is 77505.56 J.
Mc (Moscovium) has atomic number is 115
4. I meter
5. 0.453 kilometers
6. 89.84700 microns
7. Yo momma