<h3>
Answer:</h3>
1257.45 L
<h3>
Explanation:</h3>
We are given;
- Initial volume of Helium gas, V1 as 806 L
- Initial temperature of Helium gas,T1 as 20.9°C
- Initial pressure of Helium gas, P1 as 753 mmHg
- Pressure of Helium at the altitude 6.8 km, P2 as 417 mmHg
- Temperature of Helium gas at the altitude 6.8 Km, T2 as -19.1°C
But, K = °C + 273.15
Therefore, T1 = 294.05 K and T2 = 254.05 K
- We are required to calculate the new volume of the balloon at 6.8 km.
- To determine the new volume we are going to use the combined gas law.
- According to the combined gas law,

Thus, rearranging the formula;



Therefore, the volume of the balloon at an altitude of 6.8 km is 1257.45 L
Answer:
William Crookes????????????????
Answer:
0.23J/g°C
Explanation:
Given parameters:
Mass of sample = 135g
Amount of heat = 2.5kJ
Initial temperature = 19.5°c
Final temperature = 100°C
Unknown:
Specific heat capacity of the metal = ?
Solution:
The specific heat capacity of a substance is the amount of heat required to the raise the temperature of 1g of the substance by 1°C.
H = m C (T₂ - T₁ )
H is the amount of heat
m is the mass
C is the specific heat capacity
T₂ is the final temperature
T₁ is the initial temperature;
2.5 x 10³ = 135 x C x (100 - 19.5)
2500 = 10867.5C
C =
= 0.23J/g°C
Convection currents are caused by the movement of the magma in the mantle.
Hope This Helps You!
Good Luck Studying :)
This particle is a co-polymer particle with a plastic base which can easily control arbitrary thickness. It also has excellent involtage, heat and chemical resistance.
hope this helps:)sorry if it doesnt