This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:
Reaction 1: 2K⁺I⁻ + H₂⁺O₂⁻ ⇒2K⁺O⁻²H⁺ + I₂⁰
Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻
Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.
In such a way, the correct choice is C.
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where is the diagram?
without the diagram i can't help
It is a trial aimed to reduce bias during an experiment. An example would be a sugar pill, something that has no real effect so that the results of the true trial can accurately be compared. Its like a control group.
Https://us-static.z-dn.net/files/d49/33d4ec86853ef95e6f6c14242c663be4.png
Answer:
Germanium
Explanation:
The element Germanium is one with a relative molecular mass of 72. This corresponds to the mass number of this element.
Relative molecular mass of an element is the mass of a formula unit to that of a carbon-12 atom.
The chemical symbol of Germanium is Ge. It is a lustrous and hard metalloid belonging to the carbon group.
It was discovered by Clemens Alexander Winkler.
