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stich3 [128]
2 years ago
5

Convert the following 4. 100 cm = 5. 453 m = _ 6. 89847nm = _ 7. 3Mm =

Chemistry
1 answer:
fredd [130]2 years ago
6 0
4. I meter
5. 0.453 kilometers
6. 89.84700 microns
7. Yo momma
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What is the mass of 1.84 mol NaCl? Give your
Sphinxa [80]

Answer:

108 g

Explanation:

3 0
3 years ago
What is the final concentration if a 50.0 mL sample of a 15% H2SO4 solution is added to water to give a final volume of 250 mL?
Anna007 [38]

Answer:

The answer to your question is 3% H2SO4 solution

Explanation:

Data

Concentration 2 = C₂ = ?

Concentration 1 = C₁ = 15 %

Volume 1 = V₁ = 50 ml

Volume 2 = V₂ = 250 ml

Formula

             C₁V₁  = C₂V₂

Solve for C₂

             C₂ = C₁V₁ / V₂

Substitution

             C₂ = (15)(50) / 250

Simplification and result

             C₂  = 3 %

4 0
3 years ago
Calculate the amount of heat needed to evaporate 235.0 grams of water from 25.0°C to 100.0°C.
steposvetlana [31]
I hope this helps answer your question. :)

These problems are very hard to do digitally so I would recommend trying to practice these types of problems on paper :)

6 0
3 years ago
How many moles are in 1.42 x 10^25<br> molecules of NaCl?
Sholpan [36]
<h3>Answer:</h3>

23.6 mol NaCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Reading a Periodic Table
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.42 × 10²⁵ molecules NaCl

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                             \displaystyle 1.42 \cdot 10^{25} \ molecules \ NaCl(\frac{1 \ mol \ NaCl}{6.022 \cdot 10^{23} \ molecules \ NaCl})
  2. Multiply/Divide:                                                                                                   \displaystyle 23.5802 \ mol \ NaCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

23.5802 mol NaCl ≈ 23.6 mol NaCl

3 0
2 years ago
Endothermic non example
Ipatiy [6.2K]

Answer:

??????????????????????

5 0
3 years ago
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