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beks73 [17]
4 years ago
5

What element is directly below the element that has 82 protons in its nucleus

Chemistry
1 answer:
igomit [66]4 years ago
7 0
Mc (Moscovium) has atomic number is 115
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If 18.7ml of 0.01500M aqueous HCl is required to titrâtes 15.00ml of an aqueous solution of NaOH to the equivalence point, what
sweet [91]

Answer:

0.0187 M

Explanation:

Step 1: Write the balanced neutralization reaction

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

18.7 mL of 0.01500 M HCl react.

0.0187 L × 0.01500 mol/L = 2.81 × 10⁻⁴ mol

Step 3: Calculate the reacting moles of NaOH

The molar ratio of HCl to NaOH is 1:1. The reacting moles of NaOH are 1/1 × 2.81 × 10⁻⁴ mol = 2.81 × 10⁻⁴ mol.

Step 4: Calculate the molarity of NaOH

2.81 × 10⁻⁴ moles are in 15.00 mL of NaOH.

[NaOH] = 2.81 × 10⁻⁴ mol/0.01500 L = 0.0187 M

6 0
3 years ago
Jose times how long sugar takes to dissolve in warm water. He conducts four trials of his experiment. What should he conclude fr
zloy xaker [14]

Answer:

His experiment has very low precision

Explanation:

Precision is how close the answers are together. The answers are increasing in time. So, this makes sence. None of the answers are similar to one another.

5 0
3 years ago
Q2. Which of the following molecules may show.
jonny [76]

Answer:

I think is answer

CH3cl3

5 0
3 years ago
HELP! <br> A train travels 102 miles in 2 5/6 hours. What is its average speed in miles per hour?
aniked [119]

Answer:

36miles/hour

Explanation:

speed =distance÷time taken

102miles/2 5/6

102÷17/6

102×6/17

=36miles per hour

5 0
3 years ago
If 10.0 L of oxygen gas at STP are heated to 512 Celsius what will be the new volume of the gas if the pressure is also increase
uysha [10]

Answer:

16.4 L

Explanation:

we can use the combined gas law equation that gives the relationship among volume, temperature and pressure conditions of gases.

P1V1/T1 = P2V2/T2

STP conditions are standard temperature and pressure conditions

P1 is standard pressure = 1 atm , T1 is standard temperature = 273 K

and V1 is the volume

P2 is pressure, T2 is temperature and V2 is volume at the second instance

temperature is in kelvin scale,

512 ° + 273 = 785 K

substituting the values in the equation

1 atm x 10.0 L / 273 K = 1.75 atm x V / 785 K

V = 16.4 L

new volume is 16.4 L

7 0
3 years ago
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