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son4ous [18]
3 years ago
11

solid sodium reacts violently with water producing heat, hydrogen gas and sodium hydroxide. How many molecules of hydrogen gas a

re produced when 65.4g of sodium are added to water? 2Na(s)+ 2H2O(l) -->. 2NaOH(aq) + H2(g)
Chemistry
1 answer:
Blababa [14]3 years ago
5 0
Molar mass of sodium=23g
2 mole sodium gives 2 g H2
i.e 46g sodium gives 2g H2
so 65.4g will give=2.84g H2
now no. of molecules = 2.8/2*avogadros number
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Zinc would be considered the strongest reducing agent.

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2 years ago
Oxygen is denoted as 16O8. How many protons and neutrons does an oxygen atom have?
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3 years ago
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A substance joined by this type of bond has a low melting point
cestrela7 [59]
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Olympic cyclist fill their tires with helium to make them lighter. Calculate the mass of air in an air filled tire and the mass
inn [45]

<u>Answer:</u> The mass difference between the two is 7.38 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas follows:

PV=nRT

where,

P = pressure = 125 psi = 8.50 atm    (Conversion factor:  1 atm = 14.7 psi)

V = Volume = 855 mL = 0.855 L    (Conversion factor:  1 L = 1000 mL)

T = Temperature = 25^oC=[25+273]K=298K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

8.50atm\times 0.855L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{8.50\times 0.855}{0.0821\times 298}=0.297mol

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For air:</u>

Moles of air = 0.297 moles

Average molar mass of air = 28.8 g/mol

Putting values in equation 1, we get:

0.297mol=\frac{\text{Mass of air}}{28.8g/mol}\\\\\text{Mass of air}=(0.297mol\times 28.8g/mol)=8.56g

Mass of air, m_1 = 8.56 g

  • <u>For helium gas:</u>

Moles of helium = 0.297 moles

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

0.297mol=\frac{\text{Mass of helium}}{4g/mol}\\\\\text{Mass of helium}=(0.297mol\times 4g/mol)=1.18g

Mass of helium, m_2 = 1.18 g

Calculating the mass difference between the two:

\Delta m=m_1-m_2

\Delta m=(8.56-1.18)g=7.38g

Hence, the mass difference between the two is 7.38 grams.

5 0
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Hello! I am working on some homework and came across this question, which completely confuses me for various reasons. Experiment
Mariana [72]
Thats hard as hell just drop out of the class lol
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