Answer:
B. The electronegativities of the two atoms are equal.
Answer:
2.18x10^-9 M
Explanation:
From the question given,
Hydrogen ion concentration, [H+] = 4.59x10^-6 M
Hydroxide ion, [OH-] =?
The hydroxide ion concentration, [OH-] in the solution can be obtained as follow:
[H+] x [OH-] = 1x10^-14
4.59x10^-6 x [OH-] = 1x10^-14
Divide both side by 4.59x10^-6
[OH-] = 1x10^-14 / 4.59x10^-6
[OH-] = 2.18x10^-9 M
Answer:
Explanation:
Combustion reaction is given below,
C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)
Provided that such a combustion has a normal enthalpy,
ΔH°rxn = -1270 kJ/mol
That would be 1 mol reacting to release of ethanol,
⇒ -1270 kJ of heat
Now,
0.383 Ethanol mol responds to release or unlock,
(c) Determine the final temperature of the air in the room after the combustion.
Given that :
specific heat c = 1.005 J/(g. °C)
m = 5.56 ×10⁴ g
Using the relation:
q = mcΔT
- 486.34 = 5.56 ×10⁴ × 1.005 × ΔT
ΔT= (486.34 × 1000 )/5.56×10⁴ × 1.005
ΔT= 836.88 °C
ΔT= T₂ - T₁
T₂ = ΔT + T₁
T₂ = 836.88 °C + 21.7°C
T₂ = 858.58 °C
Therefore, the final temperature of the air in the room after combustion is 858.58 °C
