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Elden [556K]
3 years ago
5

If the function f(n) models the size of a jar that holds n marbles to be sold in a toy store, which describes an appropriate dom

ain for the function?
A)all integers where n>0
B)all real numbers where n>0
C)all rational numbers where n> 0
D)all rational numbers where n> 0
Mathematics
2 answers:
Nastasia [14]3 years ago
5 0

Answer:

<h2>A) all integers where n>0</h2>

Step-by-step explanation:

Notice that the number of marbles must be positive, because -5 marbles won't make any sense because objects cannot be negative. Similarly, the number of marbles must be an integer number, because they cannot be decimal, they cannot be broken into parts.

Therefore, the right answer is A, the right domain for the function is all n > 0, where n  is an integer.

Alex Ar [27]3 years ago
3 0
<span>A) All integers where n>0

[ Number of marbles can't be negative, fraction or in decimal so it must be positive integer where n is greater than the zero ]

Hope this helps!</span>
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days

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which is equal to 12 days

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-2 - 3 = -5
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5 0
3 years ago
An office manager has received a report from a consultant that includes a section on equipment replacement. the report indicates
wolverine [178]

Answer:

a) 22.663%

b) 44%

c) 38.3%

Explanation:

An office manager has received a report from a consultant that includes a section on equipment replacement. The report indicates that scanners have a service life that is normally distributed with a mean of 41 months and a standard deviation of 4 months. On the basis of this information, determine the percentage of scanners that can be expected to fail in the following time periods:

We solve the above question using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 41 months

σ is the population standard deviation = 4 months

a. Before 38 months of service

Before in z score score means less than 38 months

Hence,

z = 38 - 41/4

z = -0.75

Probability value from Z-Table:

P(x<38) = 0.22663

Converting to percentage = 0.22663 × 100

= 22.663%

b. Between 40 and 45 months of service

For x = 40 months

z = 40 - 41/4

z = -0.2

Probaility value from Z-Table:

P(x =40) = 0.40129

For x = 45

z = 45 - 41/4

z = 1

Probability value from Z-Table:

P(x = 45) = 0.84134

Between 40 and 45 months of service

= 0.84134 - 0.40129

= 0.44005

Converting to Percentage

= 0.44005 × 100

= 44.005%

= 44%

c. Wihin ± 2 months of the mean life

+ 2 months = 41 months + 2 months

= 43 month

- 2 months = 41 months - 2 months

= 39 months

For x = 43

z = 43 - 41 /4

z = 0.5

P-value from Z-Table:

P(x = 43) = 0.69146

For x = 39

z = 39 - 41/4

z = -2/4

z = -0.5

Probability value from Z-Table:

P(x = 39) = 0.30854

Within ± 2 months of the mean life

= 0.69146 - 0.30854

= 0.38292

= 38.3%

Learn more about z-score:

brainly.com/question/17436641

#SPJ4

4 0
2 years ago
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