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Serhud [2]
3 years ago
7

Factor out the coefficient of the variable 1/2d+6

Mathematics
2 answers:
IrinaK [193]3 years ago
5 0
Factoring out the 1/2 (that is the coefficient of the variable) would require you to divide the equation by one half, which is the same as multiplying by two. After doing this, the answer can be expressed as:

1/2 (d+12)
lyudmila [28]3 years ago
3 0

Answer:

The factor out coefficient of the variable is \frac{1}{2}

Step-by-step explanation:

Given : Expression \frac{1}{2}d+6

To find : Factor out the coefficient of the variable expression ?

Solution :

A coefficient is defined as a number or constant before a variable (with positive or negative sign).

In the expression, \frac{1}{2}d+6

The variable is 'd'.

Taking common constant from both terms to factor out is

\frac{1}{2}d+6=\frac{1}{2}(d+12)

Therefore, The factor out coefficient of the variable is \frac{1}{2}

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Answer:

\boxed{\pink{\tt I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C}}

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We need to integrate the given expression. Let I be the answer .

\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\  dx

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\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I =  \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C }}}}}

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suppose Faye plans to fill packets with 60 beads and after deciding not to add any yellow beads (180 beads) to the mix. If you w
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3 years ago
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