For number 3.
You add 8 to both sides as you need to separate the variable
4x-8=32
+8 +8
4x=32
now divide 32 by 4
x=8
for number 4
you use pemdas to multiply the parenthisis
2(x-5)=-20
(2•x)-(2•5)
2x-10=-20
then add 10 to both sides
2x-10=-20
+10 +10
2x=10
divide 10 by two
x=5
Use a protractor to do the problem, but try finding th answer yourself
Alex finally had $(x+110) amount of money in his account i.e. He had $100 more then before!
<u>Step-by-step explanation:</u>
Alex wrote checks on Tuesday for $30 and $40. He also made a deposit in his checking account of $180. Let's solve it step by step :
<u>Alex wrote checks on Tuesday for $30 and $40:</u>
Let's suppose Alex initially had x amount of money out of which $30 & $40 is deducted! so left amount of money is $(x-70) .
<u>He also made a deposit in his checking account of $180:</u>
Out of left money $(x-70) , Alex deposited $180 in account so new money = $(x-70) + $180 = $(x+110)
Therefore, Alex finally had $(x+110) amount of money in his account i.e. He had $100 more then before!
Use the formula T(x) = 0.01x2^x
X is the number of days.
T(8) = 0.01 x 2^8
T(8) = 0.01 x 256
T(8) = $2.56
They only have 1 common point
