Answer:
THE PRESSURE OF THE TIRE ON THE TRIP HOME AT THE ROAD SURFACE TEMPERATURE OF 32°C IS 160 kPa.
Explanation:
Initial Pressure = 75 kPa
Initial temperature = 15 °C
Final temperature = 32 °C
Final pressure = unknown
Using the combined equation of gases;
P1V1/T1 = P2V2/ T2
Since the tire will have the same volume of air in it showing that volume of constant both at the repair shop and on the road surface.
The relationship between pressure and temperature is used with constant volume.
P1/T1 = P2/ T2
75 kPa / 15 °C = P2 / 32 °C
P2 = 75 kPa * 32 °C / 15 °C
P2 = 2400 kPa °C / 15 °C
P2 = 160 kPa.
So therefore, the pressure of the tire on the trip home when the temperature of the road surface is 32°C is 160 kPa.
Answer:
B.
Explanation:
weak acids - partially dissociate to give H+
strong acids - fully dissociate to give H+
Answer:
See the explanation and examples below, please.
Explanation:
To calculate the molar mass of a substance you must have the atomic weights of each component:
Example NaCl ionic compound (sodium chloride, known as table salt)
Molar mass NaCl = Atomic weight Na + Atomic weight Cl = 22, 98 gr + 35, 45gr = 58.35 grams / mol
Example covalent compound HCl (hydrochloric acid) = Atomic weight H + Atomic weight Cl = 1, 004gr + 35, 45 gr = 36, 45 grams / mol
In the case of having compound H20 (water), it is calculated:
Molar mass NaCl = 2 x (Atomic weight H) + Atomic weight 0 (the atomic weight of 1 mol of Hydrogen is multiplied by 2)
Answer:
B. control rods and moderators
Answer:
Ratio of Vrms of argon to Vrms of hydrogen = 0.316 : 1
Explanation:
The root-mean-square speed measures the average speed of particles in a gas, and is given by the following formula:
Vrms = 
where R is molar gas constant = 8.3145 J/K.mol, T is temperature in kelvin, M is molar mass of gas in Kg/mol
For argon, M = 40/1000 Kg/mol = 0.04 Kg/mol, T = 4T , R = R
Vrms = √(3 * R *4T)/0.04 = √300RT
For hydrogen; M = 1/1000 Kg/mol = 0.001 Kg/mol, T = T, R = R
Vrms = √(3 * R *T)/0.001 = √3000RT
Ratio of Vrms of argon to that of hydrogen = √300RT / √3000RT = 0.316
Ratio of Vrms of argon to that of hydrogen = 0.316 : 1