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Mandarinka [93]
4 years ago
6

For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.

Chemistry
1 answer:
Nikolay [14]4 years ago
8 0

Explanation:

Molar mass of KClO_{3} = 39.1 + 35.5 + 3(16.0) = 122.6 g

Molar mass of KCl = 39.1 + 35.5 = 74.6 g

Molar mass of O_{2} = 32.0 g

According to the equation, 2 moles of KClO_{3} reacts to give 3 moles of oxygen.

Therefore, 2 (122.6) = 245.2 g of KClO_{3} will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of KClO_{3} gives 96.0 g of oxygen.

(a) Calculate the amount of oxygen given by 2.72 g of KClO_{3} as follows.

       \frac {96g}{245.2g} \times 2.72 g = 1.06 g of O_{2}


(b) Calculate the amount of oxygen given by 0.361 g of KClO_{3} as follows.

    \frac {96g}{245.2g} \times 0.361 g = 0.141 g of O_{2}


c) Calculate the amount of oxygen given by 83.6 kg KClO_{3} as follows.  

    \frac {96g}{245.2g} \times 83.6 g = 32.731 kg of O_{2}

Convert kg into grams as follows.

    \frac{32.731 kg}{1 kg} \times 1000 g = 32731 g of O_{2}


(d) Calculate the amount of oxygen given by 22.5 mg of KClO_{3} as follows.  

    \frac {96g}{245.2g} \times 22.5 mg = 8.79 mg

Convert mg into grams as follows.

  \frac{8.79 mg}{1 mg}\times 10^{-3} g = 8.79 \times 10^{-3} g of O_{2}

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Calculate the average atomic mass of an element containing 39.9% of atoms with a mass of 69 amu and 60.1% of atoms with a mass o
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Answer:

70.202 amu

Explanation:

From the question given above, the following data were obtained:

Isotope A:

Abundance (A%) = 39.9%

Mass of A = 69 amu

Isotope B:

Abundance (B%) = 60.1%

Mass of B = 71 amu

Average atomic mass =?

The average atomic mass of the element can be obtained as follow:

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= [(69 × 39.9)/100] + [(71 × 60.1)/100]

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4 0
3 years ago
Select the fastest way to differentiate between the organic and aqueous layers of an extraction.a. Hold a white piece of paper b
valentinak56 [21]

Answer:

b. Add a few drops of one of the layers to a test tube containing 1 mL of water. Shake the test tube to determine the solubility of the layer in water

Explanation:

Option a is not true, it depends on the compound being extracted.

Option c is not true, although most of the solvents used in extractions have lower boiling point than water there are exceptions, for example toluene.

Option  d is not true. Again most of the solvents used in extractions are less dense than water, there are many exceptions, for example chloroform, so for equal volumes the chloroform layer will weigh more.

Option b. is the correct one.

One will test the  miscibility of the layer in water. If it inmiscible then one would know is the organic layer. If it is the aqueous layer then it will completely be miscible.

6 0
3 years ago
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