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3 years ago

In right triangle PQR, tanP =sqrt 3/2. Find the length of the hypotenuse of triangle PQR.

Mathematics

1 answer:

Aleksandr [31]3 years ago

8 0

$\sqrt{ \sqrt{3}^2+2^2} = \sqrt{3+4} = \sqrt{7}$

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Find the first 5 terms of the sequence: an = 4n-1.

Ad libitum [116K]

#sol1

a1=1×4-1=3
a2=2×4-1=7
a3=3×4-1=11
a4=4×4-1=15
a5=5×5-1=19

#sol2

f(1)=1×4-1=3,
f(n+1)=f(n)+4,
so .... you know.

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3 years ago

Select the correct location on the table. Consider the following equation. Square root of 2x+3 = x/x+5 + 2 which row in the tabl

Annette [7]

Answer:

0.8 i guess

Step-by-step explanation:

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2 years ago

Write a real world situation for 15x-20<130 (greater than or equal to is the symbol)

sammy [17]

15x<130+20, 15x<150 divided both sides by 15 ,the answer is 10

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3 years ago

Tricia is going to write Patterns A, B, and C using the rule add 15. The first

8_murik_8 [283]

Answer:

The answer is "Pattern B showed number 40; each pattern is also increased as per the rule".

Step-by-step explanation:

In every sequence pattern, it recalls that rule, it adds 15 in this need to build from the specified initial estimate each sequence.

In Pattern A.

5+20+35+50+......

In Pattern B.

10+25+40+55+70+.....

In Pattern C.

15+30+45+60....

In this, pattern option B is correct because it will give 40.

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3 years ago

What is the y coordinate of the point that divides the

svet-max [94.6K]

Answer:

the y coordinate is 5

Step-by-step explanation:

In the figure attached, the directed line segment is shown.

J is located at (-3, 1) and K is located at (-8, 11)

run: x2 -x1 = -8 - (-3) = -5

rise: y2 - y1 = 11 - 1 = 10

Taking J as reference, the coordinate of the point that divides the directed line segment from J to k into a ratio of 2:3 is:

c = 2/(2+3) = 0.4

(x1 + c*run, y1 + c*rise)

(-3 + 0.4*-5, 1+0.4*10)

(-5, 5)

6 0

3 years ago