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vladimir2022 [97]
2 years ago
10

A student with an unknown code of Q3A conducts a qualitative analysis of her unknown. Her results indicated the formation of a y

ellow precipitate and a grey precipitate. From her results, what ions can you confirm were not in her unknown sample?
Chemistry
1 answer:
insens350 [35]2 years ago
6 0

Answer:

Grey precipitate implies the presence of silver ions

Yellow precipitate implies the presence of lead II ions

Explanation:

Qualitative analysis provides us a quick method of identifying ions present in a sample by chemical reactions involving simple reagents. Precipitates having a unique colour is formed. The identity of ions in the sample is deduced from the colour of precipitate obtained when particular reagents are added.

In the question, a precipitate containing silver ions upon standing turn into grey colour. Similarly, lead II ions give a yellow precipitate.

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Answer:

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Explanation:

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nexus9112 [7]

Answer:

2C₃H₇BO₃ + 8O₂ → 6CO₂ + 7H₂O + B₂O₃.

Explanation:

  • For balancing a chemical equation, we should apply the law of conversation of mass. It states that the no. of atoms in the reactants side is equal to that of the products side.

So, the balanced equation:

<em>2C₃H₇BO₃ + 8O₂ → 6CO₂ + 7H₂O + B₂O₃.</em>

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Answer:

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Explanation:

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Thus, it should be written in the undissociated form (HCN).

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Thus, it should be written in the ionic form (H⁺, Br⁻).

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Answer:

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