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2 years ago

6

Use the reaction:

2 answers:

damaskus [11]2 years ago

5 0

The answer is 34.2 mL

goblinko [34]2 years ago

3 0

Answer:

It’s either 34.2 OR 34.3 either would be correct!

Explanation:

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(BRAINLIEST)<br> Which of the compounds are used to reduce acidity of soil

Luda [366]

Explanation:

Limestone acts as a soil acid neutralizer and consists of eithercalcium and magnesium carbonate orcalcium carbonate. These are called dolomitic limestone and calciticlimestone respectively

7 0

3 years ago

Integrated rate law for second order unimolecular irreversible

kirill115 [55]

Answer:

The rate law for second order unimolecular irreversible reaction is

$\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }$

Explanation:

A second order unimolecular irreversible reaction is

2A → B

Thus the rate of the reaction is

$v = -\frac{1}{2}.\frac{d[A]}{dt} = k.[A]^{2}$

rearranging the ecuation

$-\frac{1}{2}.\frac{k}{dt} = \frac{[A]^{2}}{d[A]}$

Integrating between times 0 to <em>t </em>and between the concentrations of $[A]_{0}$ to <em>[A].</em>

$\int\limits^0_t -\frac{1}{2}.\frac{k}{dt} =\int\limits^A_{0} _A\frac{[A]^{2}}{d[A]}$

Solving the integral

$\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }$

5 0

3 years ago

How many moles of HCl would react with 37.1 mL of 0.138 M Sr(OH)2

Lena [83]

Answer is: 0.102 moles of HCl would react.

Balanced chemical reaction:

2HCl(aq) + Sr(OH)₂ → SrCl₂(aq) + 2H₂O(l).

V(Sr(OH)₂) = 37.1 mL ÷ 1000 mL/L.

V(Sr(OH)₂) = 0.0371 L; volume of the strontium hydroxide solution.

c(Sr(OH)₂) = 0.138 M; molarity of the strontium hydroxide solution.

n(Sr(OH)₂) = c(Sr(OH)₂) · V(Sr(OH)₂).

n(Sr(OH)₂) = 0.0371 L · 0.138 mol/L.

n(Sr(OH)₂) = 0.0051 mol; amount of the strontium hydroxide.

From balanced chemical reaction: n(Sr(OH)₂) : n(HCl) = 1 : 2.

n(HCl) = 2 · n(Sr(OH)₂).

n(HCl) = 2 · 0.0051 mol.

n(HCl) = 0.0102 mol; amount of the hydrochloric acid.

5 0

3 years ago

What are the smallest organelles in cell that are not enclosed in a membrance and they make protien

levacccp [35]

Ribosomes.ribosomes are small structures where proteins are made.Although they are not enclosed within a membrane,they are frequently considered organelles. Hope it helps :)

4 0

3 years ago

Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

3 0

2 years ago