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PilotLPTM [1.2K]
4 years ago
7

The time required for a citizen to complete the 2010 u.s. census "long" form is normally distributed with a mean of 40 minutes a

nd a standard deviation of 10 minutes. what is the third quartile (in minutes) for the time required to complete the form? 44.75 46.75 47.50 52.50
Mathematics
1 answer:
KiRa [710]4 years ago
6 0
The third quartile will be evaluated as follows:
z-score=(x-mu)/sig
mu=40
sig=10
the z-value corresponding to 0.75 is 0.68
hence:
0.67=(x-40)/10
solving for x we get:
6.7=x-40
x=6.7+40
x=46.7
x~46.75

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there are 62000 millilitres in 62 liters

5 0
3 years ago
Read 2 more answers
Yolanda deposits $300 per month in an account with an APR of 6%, while Zach deposits $3600 at the end
bonufazy [111]

Answer:

Yolanda will have a balance of $34,043.10 in 14 years.

Step-by-step explanation:

This is an Ordinary annuity question where you pick the hint from the equal and recurring monthly payment.

To find the Future value of Yolanda's savings after 14 years, use Future value of annuity formula FVA = \frac{PMT}{r}[1-(1+r)^{-t} ]\\

PMT= recurring payment = $300

r = discount rate; monthly rate in this case = 6% / 12 =0.5% or 0.005 as a decimal.

t = total duration ; 14 *12 = 168 months

Next, plug in the numbers into the FVA formula;

FVA = \frac{300}{0.005} [ 1-(1+0.005)^{-168} ]

FVA = 60,000 * 0.5673849

FVA = 34,043.0969

Therefore, Yolanda will have a balance of $34,043.10 in 14 years

7 0
3 years ago
I need help with these questions<br>​
Blizzard [7]
The first one is B a-b/a+b. The second one is is also B 1/2c
5 0
3 years ago
PLEASE HELPPPPP!!!!!
vivado [14]
The answer is C!!!!!!
5 0
3 years ago
In a lake there are 53 blue tail fishes and 40 yellow tail fishes. we capture 12 fishes. what is the most probable number of blu
luda_lava [24]
In general, the most probable distribution is in the ratio of the respective types, namely
Number of blue tails
=12*(53/(53+40))
=6.84
To check between 6 or 7, we use the hypergeometric distribution:

P(B=6)
=C(40,6)C(53,6)/(C(93,12)
=3838380*22957480/416579843773639
=0.211530
P(B=7)
=C(40,5)C(53,7)/(C(93,12)
=658008*154143080/416579843773639
=65563917120/269282381237
=0.243476

Hence the most probable number of blue tail fishes is 7


Note: it would be prudent to calculate P(B=8)=0.194443 to show that P(B=7) is indeed the highest value.
7 0
4 years ago
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