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mina [271]
4 years ago
12

Which of the following is the graph of f(x) = 3 sin (2x)?.

Mathematics
2 answers:
Jlenok [28]4 years ago
5 0
The general form of a function with a trigonometric sine is y=Asin(Bx+C)+D where A is the amplitude and B is the frequency. From f(x) = 3 sin (2x),   A is equal to 3 which tells us that the graph has waves that has height from -3 to 3. B equals to 2 tells us that there are two waves between 0 and 2π.The period of the function then is <span>π. The graph goes through the (0,0) point.</span>
yanalaym [24]4 years ago
4 0

graph with points at 0, 0 and pi over 4, 3 and pi over 2, 0 and 3 pi over 4, negative 3 and pi, 0 or answer B

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Answer:

30 cm^2

Step-by-step explanation:

the triangle is 36

the rectangle is 6

36-6=30

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Jordan has $55 she earns $67 by doing chores how many money does Jordan have now
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− 96 , 48 , − 24 , 12 , − 6 . what is the ratio of the geometric sequece
snow_tiger [21]

Answer:

-1/2

Step-by-step explanation:

it has to be a negative number since

every other number is negative

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96 divided by 48 is 2

so the number being multiplied or ration must be -1/2

7 0
2 years ago
Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the
Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66

t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

3 0
4 years ago
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