Question

What is the mass grams that are in 2.57 × 10²⁵ molecules of I₂

Answer 1

The mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g

From a detailed understanding of Avogadro's hypothesis, we understood 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of I₂ also 6.02×10²³ molecules i.e

6.02×10²³ molecules = 1 mole of I₂

Recall:

1 mole of I₂ = 2 × 127 = 254 g

Thus,

6.02×10²³ molecules = 254 g of I₂

With the above information, we can obtain the mass of I₂ that contains 2.57×10²⁵ molecules. This is illustrated below:

6.02×10²³ molecules = 254 g of I₂

Therefore,

2.57×10²⁵ molecules = $\frac{2.57*10^{25} * 254}{6.02*10^{23}}$

2.57×10²⁵ molecules = 10843.52 g of I₂

Thus, the mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g

Learn more: brainly.com/question/24848191