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3 years ago

Which of the following answers is the correct one, explain

Mathematics

1 answer:

Juli2301 [7.4K]3 years ago

7 0

It is the second one
it is the letter b

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Can you tern this into a equation

Aleks [24]

Answer:

n + p x 3 = t

Step-by-step explanation:

n= Navita's money

p= Pawan's money

t= total money

8 0

3 years ago

If anyone could help it would be greatly appreciated

Ira Lisetskai [31]

Answer:

Step-by-step explanation:

area of one triangle=(1/2)×6×4=12 m²

area of four triangles=4×12=48 m²

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4 years ago

Simplify the following, where k represents any integer: cos(2kpi-x)(-sin(2kpi-x))

Citrus2011 [14]

= cos( -x ) * [ - sin( - x ) ] = cosx * sinx ;
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3 years ago

The population of rabbits on an island is growing exponentially. In the year 1994, the population of rabbits was 9600, and by 20

drek231 [11]

Answer:

49243

Step-by-step explanation:

Given that the population of rabbits on an island is growing exponentially.

Let the population, $P=P_0e^{bt}$

where, $P_0$ and b are constants, t=(Current year -1994) is the time in years from 1994.

In 1994, t=0, the population of rabbit, P=9600, so

$9600=P_0e^{b\times 0}$

So, $P_0=9600$

and in 2000, t=2000-1994=6 years and population of the rabbit, P=18400

$18400=9600 \times e^{b\times 6} \\\\\frac{18400}{9600}=e^{b\times 6} \\\\$

$\ln(23/12}=6b \\\\$

$b = \frac{\ln{1.92}}{6} \\\\$

b=0.109

On putting the value of P_0 and b, the population of the rabbit after t years from 1994 is

$P=9600 \times e^{0.109\times t}$

In 2009, t= 2009-1994=15 years,

So, the population of the rabbit in 2009

$P=9600 \times e^{0.109\times 15}=49243$

Hence, the population of the rabbit in 2009 is 49243.

7 0

3 years ago

Please helllllllppppppppp

Harman [31]

(i) 2^6

(ii) 3^5

(iii) -1^14

(iv) 0.3^4

4 0

3 years ago