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Charra [1.4K]
3 years ago
6

How do you solve -2+6(-6x+6)?

Mathematics
1 answer:
Natali5045456 [20]3 years ago
4 0

Answer: −36x+34

Step-by-step explanation:

Equation: −2+6(−6x+6)

Step 1. distribute the equation:

−2+(6)(−6x)+(6)(6)

−2+−36x+36

Step 2. Finally combine like terms:

−2+−36x+36

(−36x)+(−2+36)

−36x+34

Final Answer:

−36x+34

Hope I could help! :)

You might be interested in
Find the Sum of 2/7 + 2/5. Answer should be in simplest form
solong [7]

Answer:

24/35

Step-by-step explanation:

(2/7) + (2/5) =

(2*5)/(7*5) + (2*7)/(5*7) =

10/35 + 14/35 =

24/35

3 0
4 years ago
Read 2 more answers
In a school there are 600 teachers ad 1200 students
8_murik_8 [283]

Answer:

Can you please give a clearer explanation of what is your question?

Step-by-step explanation:

8 0
4 years ago
The library at school is organized by fiction and non-fiction books. There are 3 non-fiction books for every 7 fiction books. Ho
sweet [91]

Answer:

Total = 800 books

Step-by-step explanation:

It is given that,

In a library, there are 3 non-fiction books for every 7 fiction books. It means that the ratio of non-fiction books to the fiction books is 3:7.

There if the library has 240 non-fiction books.

Let non fiction books are 3x and fiction books are 7x.

ATQ,

3x=240

x=80

Fiction books = 7x = 7(80) = 560

Total no of books = fiction books + non-fiction books

= 240 + 560

=800

Hence, the total no of books are 800.

7 0
3 years ago
a sheep breeding farm counted a total of 40 sheep on their grounds after one year the number of sheep doubled then in the next y
SpyIntel [72]
Answer:
graph (b)

Explanation:
The farm started with 40 sheep and the number doubled each year.
So, the equation modeling this situation would be:
N(x) = 40*(2)^2
By getting the equation, we can notice that we already excluded the third and fourth choices as they have the wrong equations.

Now, we will need to select the right graph which is either graph a or graph b.
To do this, we will get the value of N(x) for different values of x as follows:
At x = 0: N(0) = 40*(2)^0 = 40
At x = 1: N(1) = 40*(2)^1 = 80
At x = 1: N(2) = 40*(2)^2 = 160

Now, taking a look at graph a, we will find that:
N(1) = 120
N(2) = 360
These numbers are not the same as the numbers we calculated, therefore, this graph is wrong

Taking a look at graph b, we will find that:
N(1) = 80
N(2) = 160
These numbers are exactly the same as the ones calculated, therefore, this graph is the correct one.

Hope this helps :)
7 0
4 years ago
Suppose Brianna decided that the error margin of her 95% confidence interval was too large and wanted an error margin of .05 whi
svetoff [14.1K]

Answer:

n=\frac{0.26 (1-0.26)}{(\frac{0.05}{1.96})^2} =295.65 \approx =296 (b)  

Rounded up would be n =296

Step-by-step explanation:

Assuming this previous info:  She randomly interested in the p selects 100 engineering majors, and 26 of them said they earned an A in Calc 1.

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.96  

Thes estimated proportion is \hat p = \frac{26}{100}=0.26

And replacing we got:

n=\frac{0.26 (1-0.26)}{(\frac{0.05}{1.96})^2} =295.65 \approx =296 (b)  

3 0
3 years ago
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