<h2>Two wrinkled seeds combination in cross test</h2>
Explanation:
Whenever one or more of the parents' genes are dominant, the resulting daughter gene will be dominant.
Thus, in order to produce a recessive gene, BOTH parent genes must be recessive as well. Because wrinkled genes are recessive, you're going to need both wrinkled genes.
For example, when Mendel cross-prepared plants with wrinkled seeds to those with smooth seeds, he didn't get descendants with semi-wrinkly seeds. Rather, the descendants from this cross had just smooth seeds.
It must have two wrinkled genes.
Hence, the combination of genes are two wrinkled seeds is the right answer.
The wrinkled pea will have two recessive alleles on the locus.
Explanation:
Two forms of same gene are called alleles of that gene.
The allele that expresses itself under heterozygous condition is called the Dominant allele.
The recessive allele can express itself only if they are under homozygous combination i.e. both the alleles on homologous chromosome are recessive.
Here wrinkled pea is a recessive trait and if it is expressed in the phenotype then the genotype of the plant must be homozygous for the recessive allele.
False the process is reversed. Photosystem ll happens before photosystem l. I know that's weird but it's true. In photosystem ll which happens first it makes the energy carriers for ATP Synthase to happen in Photosystem l which is the next phase. Hope this helped!
The answer is both in males and females; only in males. Males
have one Y chromosome and one X chromosome, while females
have two X chromosomes. In mammals, the Y chromosome controls a
gene which is the SRY, which produces embryonic improvement as a male. The Y chromosomes of males and
other mammals also contain other genes needed for normal sperm production.
