Answer:
2.95 g of CH₄
Explanation:
To start this, we determine the equation:
4H₂ + CO₂ → CH₄ + 2H₂O
4 moles of hydrogen react to 1 mol of carbon dioxide in order to produce 1 mol of methane and 2 moles of water.
To determine the limiting reactant, we need to know the moles of each reactant.
8.1 g . 1 mol/ 44g = 0.184 moles of carbon dioxide
2.3 g . 1mol / 2g = 1.15 moles of hydrogen
4 moles of hydrogen react to 1 mol of CO₂
Then, 1.15 moles may react to (1.15 . 1) /4 = 0.2875 moles
We only have 0.184 moles of CO₂, so this is the limiting reactant. Not enough CO₂ to complete the 0.2875 moles that are needed.
Ratio is 1:1. 1 mol of CO₂ produces 1 mol of methane
Then, 0.184 moles of CO₂ will produce 0.184 moles of CH₄
We convert moles to mass: 0.184 mol . 16 g /mol = 2.95 g
Answer:
Volume in litter = 0.8 L
Explanation:
Given data:
Mass of KOH = 112 g
Molarity of KOH = 2.5 M
Volume = ?
Solution:
Number of moles of KOH:
Number of moles = mass/ molar mass
Number of moles = 112 g/ 56 g/mol
Number of moles = 2 mol
Volume of KOH:
Molarity = number of moles / volume in litter
Volume in litter = number of moles / Molarity
Volume in litter = 2 mol / 2.5 mol/L
Volume in litter = 0.8 L
Lithium. Electronegativty increases across the periodic table and increases down the periodic table.
Answer:
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