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Vinvika [58]
3 years ago
6

!!!PLEASE HELP ASAP!!!!consider this reaction:

Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0
9L!!! You take the moles of N2 in the reaction and then divide by one mole of nitrogen. Then you multiply that by the number of hydrogen moles in the reaction which in this case is 3. This gives you an answer of 3. You then take the number of hydrogen moles and multiply it by the 3L giving you 9L of hydrogen.
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Answer:

The answer to your question is 900 g of water vapor

Explanation:

Data

mass of H₂O = ?

mass of butane = 580 g

Balanced chemical reaction

             2C₄H₁₀ + 13O₂  ⇒  8CO₂  +  10H₂O

Process

1.- Calculate the molar weight of butane and water

Butane (C₄H₁₀) = 2[(12 x 4) + (1 x 10)]

                         = 2[48 + 10]

                         = 2[58]

                         = 116 g

Water (H₂O) = 10[(1 x 2) + (1 x 16)]

                    = 10[2 + 16]

                    = 10[18]

                    = 180 g

2.- Use proportions and cross multiplication to find the mass of water vapor

             116 g of butane ------------- 180 g of water

             580 g of butane  ----------  x

                x = (580 x 180) / 116

                x = 900 g of water vapor

3 0
3 years ago
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