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valkas [14]
3 years ago
5

Integrate ​G(x,y,z)equalsz over the parabolic cylinder yequalszsquared​, 0less than or equalsxless than or equals2​, 0less than

or equalszless than or equalsStartFraction StartRoot 15 EndRoot Over 2 EndFraction . Write the integral ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing With Upper S Upper G (x comma y comma z )d sigma as a double integral. ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing With Upper S Upper G (x comma y comma z )d sigmaequalsIntegral from nothing to nothing Integral from nothing to nothing nothing dz dx.
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
5 0

I gather you're supposed to compute the integral of G(x,y,z)=z over a surface S that is the part of the parabolic cylinder y=z^2 with 0\le x\le2 and 0\le z\le\frac{\sqrt{15}}2.

We can parameterize S by

\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k

with the given constraints on x and z. Take the normal vector to S to be

\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k

so that the surface element is

\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz

Then in the integral, we have

\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}

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