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Alisiya [41]
4 years ago
11

Working together, it takes two different sized hoses 30 minutes to fill a small swimming pool. If it takes 50 minutes for the la

rger hose to fill the swimming pool by itself, how long will it take the smaller hose to fill the pool on its own
Mathematics
2 answers:
katrin2010 [14]4 years ago
8 0

Answer:

75 minutes

Step-by-step explanation:

Let's call the volume of the pool by V.

If the larger hose takes 50 minutes to fill the pool, the amount of water this hose fills is V/50

Let's call the amount of time the small hole takes to fill the pool on its own by T, so its speed is V/T

The two holes together fill the pool in 30 minutes, so their speed summed is V/30:

V/50 + V/T = V/30

Dividing the equation by V, we have:

1/50 + 1/T = 1/30

(3T + 150)/150T = 5T/150T

3T + 150 = 5T

2T = 150

T = 75 minutes

Oduvanchick [21]4 years ago
7 0

Answer:

75 minutes

Step-by-step explanation:

In this question, we are asked to calculate the time it will take a smaller hose out of two hoses to fill a swimming pool by itself.

Firstly, let’s say the volume of the swimming pool to fill is Xm^3.

Hence for both, the rate of filling is x/30 m^3/minutes. For the larger hose, rate will be x/50 m^3/minutes. For the larger hose, let the time taken be z minutes. It’s rate will be x/z m^3/minute.

Mathematically, adding both rates together give the rate of both at the same time. This means;

X/30 = x/50 + x/z

X/z = x/30 - c/50

x/z = 20/1500

x/z = 1/75

z = x/75

This means the time that it will take the smaller hose will be 75 minutes

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Vikentia [17]

Answer:

P(B/C) = 0.3333

Step-by-step explanation:

let's call B the event that a woman was wearing a belt and C the event that a woman was carrying a purse.

The probability P(B/C) that a woman was wearing a belt, given that the woman was also carrying a purse can be calculated as:

P(B/C) = P(B∩C)/P(C)

Where P(C) is the probability that a woman was carrying purse and P(B∩C) is the probability that the woman was both carrying purse and wearing belt.

So, P(C) is calculated as:

P(C) = 18 / 30 = 0.6

Because there were 30 women that walked by in an hour and of those women, 18 were carrying purses.

At the same way, P(B∩C) is equal to:

P(B∩C) = 6 / 30 = 0.2

Finally, P(B/C) is equal to:

P(B/C) = 0.2/0.6 = 0.3333

4 0
3 years ago
Read 2 more answers
In a G.P., the third term exceeds the first term by 16.
Tresset [83]

Answer:

Step-by-step explanation:

In a G.P, the nth term is given as

Un=ar^(n-1)

Where

a is first term

n is nth term

And r is common ratio

So in the question given above,

The third term exceed the first term by 16

i.e U3=U1+16

Where U1=a. First term

U3=a+16

Given also that, the sum if the third term and fourth term is 72.

Then U3+U4=72.

We are told to find common ratio (r)

U3=ar^3-1

U3=ar^2

Also, U4=ar^3

U3+U4=72

ar^2+ar^3=72

ar^2(1+r)=72. equation 1

Also for

U3=a+16

ar^2=a+16

ar^2-a=16

a(r^2-1)=16. From (x^2-y^2)=(x+y)(x-y)

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a(r-1)(r+1)=16. Equation 2

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9(r-1)=2r^2

2r^2-9r+9=0

Solving the quadratic equation

2r^2-6r-3r+9=0

2r(r-3)-3(r-3)=0

(r-3)(2r-3)=0

r-3=0. Or. 2r-3= 0

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8 0
3 years ago
Need help please! Can someone explain?
Lynna [10]

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A=(3.14)3^2

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A=28.26ft^2

Hope it helps and is correct :)

3 0
3 years ago
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coldgirl [10]

Answer:

a=-2

We move all terms to the left:

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We multiply parentheses

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We get rid of parentheses

4a-5a-2+6-6=0

We add all the numbers together, and all the variables

-1a-2=0

We move all terms containing a to the left, all other terms to the right

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Step-by-step explanation:

We move all terms to the left:

2(2a+3)-6-(5a+2)=0

We multiply parentheses

4a-(5a+2)+6-6=0

We get rid of parentheses

4a-5a-2+6-6=0

We add all the numbers together, and all the variables

-1a-2=0

We move all terms containing a to the left, all other terms to the right

-a=2

a=2/-1

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Please like and give me Brainliest!

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serg [7]

Answer:

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Step-by-step explanation:

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4 years ago
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