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Dmitry [639]
4 years ago
3

Pulleys and block-and-tackles are often used to hoist objects into the upper levels of barns and garages. The supports that hold

these contraptions come in various forms. Let us model the illustrated orange support as a planar truss with horizontal member AC that is subjected to the vertical tension load T . Given the following: T= 90 N AB=100 cm AC 140 cm ?=25. Determine forces F_AB, F_AC, and F_BC in N in members AB, AC, and BC.
Engineering
1 answer:
kompoz [17]4 years ago
7 0

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Horizontal shear forces and, consequently, horizontal shear stresses are caused in a flexural member at those locations where th
jek_recluse [69]

Answer:

False

Explanation:

When the horizontal shear forces act on the surface there is transverse shear stress at a particular point which is equal in magnitude. Pure bending is less common than a non uniform bending because the beam is not in equilibrium.

5 0
3 years ago
The man of mass m1 = 82 kg and the woman of mass m2 = 80 kg are standing on opposite ends of the platform of mass m0 = 103 kg wh
german

Answer:

Δs = 0.0679 m

Explanation:

m₀ = 103 kg

m₁ = 82 kg

m₂ = 80 kg

x₀ = (L/2) = (15.5/2) m = 7.75 m

Initial positions

x₁ = 0 m

x₂ = L = 15.5 m

Final positions

x₁ = 9 m

x₂ = L – x₁ = 15.5 m – 9 m = 6.5 m

Xcm = (m₀*X₀+m₁*X₁+m₂*X₂) / (m₀+m₁+m₂)

We get the center of mass in every case

Xcm initial = (103 Kg *7.75 m +82 Kg*0 m+ 80 Kg*15.5 m)/(103+82+80) Kg = 7.6915 m

Xcm final = (103 Kg *7.75 m +82 Kg*9 m+ 80 Kg*6.5 m)/(103+82+80) Kg = 7.7594 m

Variation: Δs = Xcm final - Xcm initial = 7.7594 m - 7.6915 m = 0.0679 m

6 0
4 years ago
What is the condition for sampling frequency to reconstruct the information signal ?​
bagirrra123 [75]

A continuous time-varying 1-D signal is sampled by narrow sampling pulses at a regular rate fr = 1/T, which must be at least twice the bandwidth of the signal. At first, it may be somewhat surprising that the original waveform can be reconstructed exactly from a set of discrete samples.
8 0
3 years ago
.............................................
Akimi4 [234]
....................................
5 0
3 years ago
You are given a collection of n bottles of different widths and n lids of different widths and you need to find which lid goes w
Sladkaya [172]

Answer:

void bubble_sort( int A[ ], int n ) {

     int temp;

     for(int k = 0; k< n-1; k++) {

          // (n-k-1) to ignore comparisons of already compared iterations

         for(int i = 0; i < n-k-1; i++) {

                 if(A[ i ] > A[ i+1] ) {

                      // swapping occurs here

                      temp = A[ i ];

                      A[ i ] = A[ i+1 ];

                      A[ i + 1] = temp ;

                  }

          }

    }

}

5 0
3 years ago
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