std::string x[n]; int mode1count = 0; // msft int mode2count = 0; // appl int mode3count = 0; // csco int mode4count = 0; // imb

Question

3 years ago

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std::string x[n]; int mode1count = 0; // msft int mode2count = 0; // appl int mode3count = 0; // csco int mode4count = 0; // imb

int i; for(i = 0; i < n; ++i) // Set the array of strings x[i] = modeList[i]; for(i = 0; i < n; ++i) { if(x[i] == "msft") ++mode1count; else if(x[i] == "appl") ++mode2count; else if(x[i] == "csco") ++mode3count; else if(x[i] == "imb") ++mode4count; }

Engineering

1 answer:

rosijanka [135] · Answer 1 · 2022-04-22T19:36:25+03:00

Answer:

std::string x[n];

int mode1count = 0; // msft

int mode2count = 0; // appl

int mode3count = 0; // csco

int mode4count = 0; // imb

int i;

for(i = 0; i < n; ++i) // Set the array of strings

x[i] = modeList[i];

for(i = 0; i < n; ++i)

{

if(x[i] == "msft")

++mode1count;

else if(x[i] == "appl")

++mode2count;

else if(x[i] == "csco")

++mode3count;

else if(x[i] == "imb")

++mode4count;

}

Explanation:

It is important to ensure that there is adequate space and necessary punctuation when developing codes and programming to avoid getting error messages when running the codes. In this problem, the codes required are shown in the answer section. The codes are properly writing and arranged.