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3 years ago

A 10-V battery supplies a constant current of 0.5 amp to a resistance for 30 min.

Engineering

1 answer:

Rama09 [41]3 years ago

5 0

Answer:

a)R=20 ohm

b)W= 9 KJ

Explanation:

Given that

Voltage difference ,ΔV= 10 V

Current ,I = 0.5 A

Resistance = R

time = 30 min = 30 x 60 s = 1800 s

We know that

ΔV= I R

$R=\dfrac{10}{0.5}\ ohm$

R=20 ohm

The power P = V I

P = 10 x 0.5 = 5 Watt ( 1 watt = J/s)

We know that

$P=\dfrac{W}{t}$

W=work

t=time

W = P t

W= 5 x 1800 J

W= 9000 J =9 KJ

W= 9 KJ

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