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3 years ago

Kim is thinking of two numbers the quotient is 4 and the difference is 27 what are the two numbers

Mathematics

1 answer:

Ymorist [56]3 years ago

5 0

9 an 36 are the two numbers that Kim is thinking because

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X - 7.57=5.28 solve for x

sesenic [268]

Answer:

x = 12.85

Step-by-step explanation:

<u>Step 1: Solve for x by adding 7.57 to both sides</u>

x - 7.57 + 7.57 = 5.28 + 7.57

x = 12.85

Answer: x = 12.85

8 0

3 years ago

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Which ordered pairs lie on the graph of the exponential function f(x)=−3^2x+5 ? Select each correct answer. (−2, 76) (

In-s [12.5K]

Plugging in values, we get that (1,-4) works.

$f(1)=-3^{2*1}+5=-3^2+5=-9+5=-4$

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3 years ago

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What is the answer to x=

Elodia [21]

Answer:

It means Variable in Math

Step-by-step explanation:

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3 years ago

25x^-4-99x^-2-4=0 <br> How do I solve for this?

OlgaM077 [116]

Given

$25x^{-4} - 99x^{-2} - 4 = 0$

consider substituting $y=x^{-2}$ to get a proper quadratic equation,

$25y^2 - 99y - 4 = 0$

Solve for $y$ ; we can factorize to get

$(25y + 1) (y - 4) = 0$

$25y+1 = 0 \text{ or } y - 4 = 0$

$y = -\dfrac1{25} \text{ or }y = 4$

Solve for $x$ :

$x^{-2} = -\dfrac1{25} \text{ or }x^{-2} = 4$

The first equation has no real solution, since $x^{-2} = \frac1{x^2} > 0$ for all non-zero $x$ . Proceeding with the second equation, we get

$x^{-2} = 4 \implies x^2 = \dfrac14 \implies x = \pm\sqrt{\dfrac14} = \boxed{\pm \dfrac12}$

If we want to find all complex solutions, we take $i=\sqrt{-1}$ so that the first equation above would have led us to

$x^{-2} = -\dfrac1{25} \implies x^2 = -25 \implies x = \pm\sqrt{-25} = \pm5i$

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2 years ago

The diagram shows squares 1, 2, and 3 constructed on the sides of a right<br> triangle.

jeyben [28]

Answer:

I think D but I'm not sure about that

5 0

3 years ago

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