Hi! In 3 seconds the object will fall approximately 44 meters.
        
             
        
        
        
Answer:

Explanation:
The magnitude of the net force exerted on q is known, we have the values and positions for  and q. So, making use of coulomb's law, we can calculate the magnitude of the force exerted by
 and q. So, making use of coulomb's law, we can calculate the magnitude of the force exerted by on q. Then we can know the magnitude of the force exerted by
 on q. Then we can know the magnitude of the force exerted by  about q, finally this will allow us to know the magnitude of
 about q, finally this will allow us to know the magnitude of 
 exerts a force on q in +y direction, and
 exerts a force on q in +y direction, and  exerts a force on q in -y direction.
 exerts a force on q in -y direction.

The net force on q is:

Rewriting for  :
:

 
        
             
        
        
        
Answer:
( )=1913.31 N/m^2
)=1913.31 N/m^2
Explanation:
given:
 =0.85
=0.85
 =90 m/s
=90 m/s
γ∞=1.23 kg/m^3
solution:
since outside pressure is atm pressure vaccum can be defined by ( )
)
 =√2(
=√2( )/γ∞[
)/γ∞[ -1]
-1]
( )=1913.31 N/m^2
)=1913.31 N/m^2
 
        
             
        
        
        
Your teacher is right. The moon can be seen early in the morning sometimes and late at night. Different phases are only visible on certain days as one day might be full quarter, the next full moon, the next first quarter, etc.