Answer:
the answer is 49ft/s
Explanation:
if you look for the equations of uniformly accelerated motion you find the following
Vo=Vf-AT
Where
Vo=initial speed
Vf=final speed
A=aceleration
T=time
you replace and it's all
Vo=55-2x3
Vo=49ft/s
The effective temperature of a star is relative to the
fourth root of the luminosity and is contrariwise proportional to the square
root of the radius.
L = k R² T⁴
If the radius remains continuous, while the luminosity doubles, the temperature
must increase by a factor of the fourth root of two.
If L → 2L, then T → 1.189207115 T
So the answer is approximately 1.19 times.
D cause u can measure how powerful that wave was
Answer:
Kepler's laws apply: First Law: Planetary orbits are elliptical with the sun at a focus. Second Law: The radius vector from the sun to a planet sweeps equal areas in equal times. Third Law: The ratio of the square of the period of revolution and the cube of the ellipse semimajor axis is the same for all planets.
Try looking up the lesson and book name on the internet. then put "answer sheet"