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vagabundo [1.1K]
3 years ago
5

The city of San Francisco reported more missing dogs the week before a massive earthquake than any other week of the year. There

fore, this is factual evidence that dogs can sense impending danger.
Physics
2 answers:
navik [9.2K]3 years ago
5 0

Answer:

An earthquake constitutes the motion of seismic waves underneath the earth's surface, which humans can not sense. But, these waves generate infrasonic noise–a sound with a frequency lower than 20 Hertz and Dogs sense that something strange is happening, so they begin to be peculiar.

Explanation:

There are many observations on how dogs often begin to behave unusually right before an earthquake. An earthquake constitutes the motion of seismic waves underneath the earth's surface, which humans can not sense. But, these waves generate infrasonic noise–a sound with a frequency lower than 20 Hertz and Dogs sense that something strange is happening, so they begin to be peculiar.

Ghella [55]3 years ago
3 0
This is an example of the logic fallacy called " post hoc ergo propter hoc", meaning roughly "after that, therefore caused by that". Another example: 99.99% of the people arrested for public drunkenness in the US last month had ice in their last three mixed drinks. Therefore, this is factual evidence that ice makes people drunk.
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Dragsters can actually reach a top speed of 145.0 m/s in only 4.45 s. (a) Calculate the average acceleration for such a dragster
astraxan [27]

Answer:

a) 32.58 m/s²

b) 161.84 m/s

Explanation:

Initial velocity = u = 0

Final velocity = v = 145 m/s

Time taken = t = 4.45 s

s = Displacement of dragster = 402 m

a = Acceleration

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{145-0}{4.45}\\\Rightarrow a=32.58\ m/s^2

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as-u^2}\\\Rightarrow v=\sqrt{2\times 32.58\times 402-0^2}\\\Rightarrow v=161.84\ m/s

The final velocity is greater than the velocity used to find the average acceleration due to the gear changes. The first gear in a dragster has the most amount of toque which means the acceleration will be maximum. The final gears have less torque which means the acceleration is lower here. The final gears have less acceleration but can spin faster which makes the dragster able to reach higher speeds but slowly.

7 0
3 years ago
How many newton-meters are equal to 1600 joules
Salsk061 [2.6K]
1 Joule IS 1 newton-meter.
7 0
3 years ago
Dos cargas puntuales (q1 y q2 ) se atraen inicialmente entre sí con una fuerza de 550 N , si la separación entre ellas es de 90
antiseptic1488 [7]

Answer:

q2 = 9.02*10^{-4}C

Explanation:

To find the value of the other charge you use the Coulomb's law:

F=k\frac{q_1q_2}{r^2}

k: Coulomb's constant = 8.98*10^{9}Nm^2/C^2

q1: charge 1 = 55*10^{-6}C

r: distance between charges = 90cm = 0.9m

F: electric force = 550N

By doing q2 the subject of the formula and replacing you obtain:

q_2=\frac{r^2F}{kq_1}=\frac{(0.9m)^2(550N)}{(8.98*10^9Nm^2/C^2)(55*10^{-6}C)}=9.02*10^{-4}C

hence, the value of the other charge q2 is 9.02*10^{-4}C

6 0
3 years ago
(a) A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by driving up a 32º ramp at a speed
stiks02 [169]

a) 7 buses

b) 6.8 m

Explanation:

a)

The motion of the motorcycle is a projectile motion, so it consists of 2 independent motions:

- A uniform motion along the horizontal direction

- A uniformly accelerated motion along the vertical direction

The initial components of the velocity of the motorcycle are:

v_x = u cos(32^{\circ})=(40.0)(cos 32^{\circ})=33.9 m/s\\v_y = u sin(32^{\circ})=(40.0)(sin 32^{\circ})=21.2 m/s

The equation for the vertical motion of the motorcycle is

y=h+u_y t - \frac{1}{2}gt^2

where

y is the altitude at time t

h is the initial height

g=9.8 m/s^2 is the acceleration due to gravity

The bus top is at the same height of the initial ramp, so we have

y=h

And therefore, we can solve the equation for t, to find the time of flight:

0=u_y t - \frac{1}{2}gt^2\\t(u_y-\frac{1}{2}gt)=0\\t=\frac{2u_y}{g}=\frac{2(21.2)}{9.8}=4.33 s

Now we find what is the horizontal distance covered by the motorcycle in its jump, which is given by:

d=v_x t = (33.9)(4.33)=146.8 m

And since each bus has a length of L = 20.0 m, the number of buses that the motorcycle can clear with its jump is:

n=\frac{d}{L}=\frac{146.8}{20}=7.34

So, 7 buses.

b)

In the previous problem, we saw that the total range of the motion of the motorcycle is

d=146.8 m

And we said that this corresponds to 7 buses.

Each bus has a length of

L = 20 m

So, the total length of 7 buses is

L' = 7L=7(20)=140 m

Therefore, the range of the motorcycle is greater than the length of the buses by:

\Delta x = d-L'=146.8-140 = 6.8 m

which means he will miss the last bus by 6.8 meters.

6 0
3 years ago
I'm what case are differences isotopes important?
Reptile [31]

while discovered less than 100 years ago isotopes are now used in a wide variety of scientific applications that touch the lives of almost every citizen.

5 0
3 years ago
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