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il63 [147K]
3 years ago
11

If the tan of angle x is twenty two fifths and the triangle was dilated to be two times as big as the original, what would be th

e value of the tan of x for the dilated triangle?
Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

22/5

Step-by-step explanation:

The sides increase but in the same ratio,

Hence opposite/adjacent for image and pre image is the same ratio.

Therefore, tanX is 22/5

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the length of a rectangle is 9 centimeters more than the width. the area is 112 square centimeters. find the length and width of
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Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
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