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masya89 [10]
3 years ago
15

Can someone help me :(

Mathematics
2 answers:
BartSMP [9]3 years ago
7 0

Answer:

center of focus

Step-by-step explanation:

i hope this help "whole lotta love" NUNU

bazaltina [42]3 years ago
3 0

Answer:

The answer is B. Two Foci, hope this helps! :)

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Eleven less than three times a number
Ber [7]
The answer to this question could be 44
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3 years ago
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Which equation has the solutions x=1+or-square root of 5?
stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> x^{2}+2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=-4+1

x^{2}+2x+1=-3

Rewrite as perfect squares

(x+1)^{2}=-3

(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i

therefore

case a) is not the solution of the problem

<u>case b)</u> x^{2}-2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=-4+1

x^{2}-2x+1=-3

Rewrite as perfect squares

(x-1)^{2}=-3

(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i

therefore

case b) is not the solution of the problem

<u>case c)</u> x^{2}+2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=4+1

x^{2}+2x+1=5

Rewrite as perfect squares

(x+1)^{2}=5

(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}

therefore

case c) is not the solution of the problem

<u>case d)</u> x^{2}-2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=4+1

x^{2}-2x+1=5

Rewrite as perfect squares

(x-1)^{2}=5

(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

x^{2}-2x-4=0

5 0
3 years ago
Read 2 more answers
Select the procedure that can be used to show the converse of the
Vera_Pavlovna [14]

Answer:

The correct option is C

Step-by-step explanation:

I attached an image that forms the complete question.

The converse Pythagorean theorem states that, "If the square of the longest side of a triangle is equal to the square of the other two sides, then the triangle is a right triangle."

That is if c is the longest side of a triangle and then a and b are the other sides, then if,

c² = a² + b², the triangle is a right triangle.

Looking at all the options, option C fits the theorem well. Because

3² + 4² = 5² implies the triangle is a right triangle and the converse theorem is established.

The option D also looks close, but it's not correct because you can just draw any two sides and put the right angle in between them. The longest is always the part of the triangle that is opposite to the right angle, 90°. If for instance, you draw 3 and 5 then put the right angle in between them, 4 will take the position of the longest side which is wrong.

Therefore, the correct option is c.

7 0
3 years ago
Hey
Ray Of Light [21]
To find the first blank, just replace x in the equation with 12 and solve.
a(12) = 50 - 1.25(12) = your answer for blank 1

For blank 2: because x represents the number of apps on her phone, and x is given 12 for this problem, she bought 12 apps.

For blank 3: You would mention how many apps she got twice, so not the first option or the third option. It should be the answer from the first blank because the equation represents how much money is in her account.
7 0
3 years ago
What is the value of 1/2 ÷ 1/3? Use pattern blocks to represent and find this value. The yellow hexagon represents 1 whole. Expl
ziro4ka [17]
1/2 x 3 = 3/2 or 1.5 or 1 1/2
4 0
3 years ago
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