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Lunna [17]
3 years ago
11

Because the soles of your shoes have cleats, you can exert a forward force of 100 N even on slippery ice. A 10-kg picnic cooler

is at rest on a frozen pond, and you want to get it to shore, up the bank, and stuck in the snow. From past experience, you know that, in order to move up the bank and stick, the cooler needs to be moving at 3.0 m/s at the instant it starts up the bank. Standing some distance from the cooler and not wanting to walk to it, you decide to throw 1.0-kg snowballs at it to get it moving. If each snowball smashes into the cooler in a totally inelastic collision, what minimum number of snowballs must you throw?
Physics
1 answer:
Brilliant_brown [7]3 years ago
7 0

Answer:

you must throw 3 snowballs

Explanation:

We can solve this exercise using the concepts of conservation of the moment, let's define the system as formed by the refrigerator and all the snowballs. Let's write the moment

Initial. Before bumping that refrigerator

          p₀ = n m v₀

Where n is the snowball number

Final. When the refrigerator moves

         pf = (n m + M) v

The moment is preserved because the forces during the crash are internal

        n m v₀ = (n m + M) v

        n m (v₀ - v) = M v

        n = M/m    v/(vo-v)

Let's look for the initial velocity of the balls, suppose the person throws them with the maximum force if it slides in the snow (F = 100N), let's use the second law and Newton

          F = m a

          a = F / m

The distance the ball travels from zero speed to maximum speed is the extension of the arm (x = 1 m), let's look kinematically for the speed of the balls when leaving the arm

          v₁² = v₀² + 2 a x

          v₁² = 0+ 2 (100/1) 1

          v₁ = 14.14 m / s

This is the initial speed for the crash

         v₀ = v = 14.14 m / s

  Let's calculate

           n = M/m   v/ (v₀-v)

           n = 10/1   3 / (14.14 -3)

          n = 2.7 balls

you must throw 3 snowballs

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Answer:

536,904 J/s

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The energy output from motor is the input energy in the machine.

We know that efficiency is percentage energy ouput to energy input, and expressed as

n=\frac {E_o}{E_i}

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Energy output=0.6*1200 hp=720 hp

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7 0
1 year ago
24 POINTS!!!!!!!!!!!!!!!
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Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
P.E. = 5880

Kinetic Energy (Final One) = 1/2 mv²
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Lost Energy = 5880 - 3000 = 2880 J

In short, Your Answer would be 2880 Joules

Hope this helps!
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