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Andru [333]
3 years ago
12

A large drill is used to make a hole through rocks in the earths surface to excavate for oil

Physics
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:

\Delta GPE = mg\Delta h

Explanation:

The gravitational potential energy of an object is the energy possessed by the object due to its location in the gravitational field.

This energy is always measured as a difference with respect a "zero level" - generally taken as the ground level.

Therefore, it generally makes more sense to measure the change in gravitational potential energy of an object when its height is changed; this is given by:

\Delta GPE = mg\Delta h

where:

m is the mass of the object

g=9.8 m/s^2 is the acceleration due to gravity

\Delta h is the change in height of the object

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Earthquakes usually occur on or near: cities roads fault lines lakes
vivado [14]

Answer:

Fault lines

Explanation:

Earthquakes are most likely to occur near or on fault lines. A great example of this is the ring of fire, a gigantic fault line that gives catastrophic earthquakes.

3 0
3 years ago
Read 2 more answers
Suppose that, while lying on a beach near the equator of a far-off planet watching the sun set over a calm ocean, you start a st
zubka84 [21]

Answer:

R=3818Km

Explanation:

Take a look at the picture. Point A is when you start the stopwatch. Then you stand, the planet rotates an angle α and you are standing at point B.

Since you travel 2π radians in 24H, the angle can be calculated as:

\alpha =\frac{2*\pi *t}{24H}  t being expressed in hours.

\alpha =\frac{2*\pi *11.9s*1H/3600s}{24H}=0.000865rad

From the triangle formed by A,B and the center of the planet, we know that:

cos(\alpha )=\frac{r}{r+H}  Solving for r, we get:

r=\frac{H*cos(\alpha) }{1-cos(\alpha) } =3818Km

6 0
3 years ago
As a train enters the station it slows down from 40 m/s to a 10 m/s in 5 seconds
lora16 [44]

Answer:

See the answers below.

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f}=v_{o}-a*t

where:

Vf = final velocity = 10 [m/s]

Vo = initial velocity = 40 [m/s]

t = time = 5 [s]

a = acceleration [m/s²]

Now replacing:

10=40-a*5\\40-10=a*5\\30=5*a\\a=6[m/s^{2}]

Note: The negative sign in the above equation means that the velecity is decreasing.

2)

To solve this second part we must use the following equation of kinematics.

v_{f}^{2} =v_{o}^{2} -2*a*x\\

where:

x = distance [m]

(10)^{2} =(40)^{2} -2*6*x\\100=1600-12*x\\12*x=1600-100\\12*x=1500\\x=125[m]

7 0
3 years ago
Ice skaters often end their performances with spin turns, where they spin very fast about their center of mass with their arms f
nekit [7.7K]

Answer:

Her angular speed (in rev/s) when her arms and one leg open outward is 1.4 rev/s

Explanation:

given information:

moment inertia of arm and leg when in, I₁ = 0.9 kgm²

moment inertia of arm and leg when extended, I₂ = 2.9 kgm²

angular speed when in, ω₁ = 4.5 rev/s

so, her angular speed (in rev/s) when her arms and one leg open outward is

L₁ = L₂

I₁ω₁ = I₂ω₂

ω₂ = I₁ω₁/I₂

     = 0.9 x 4.5/2,9

     = 1.4 rev/s

4 0
3 years ago
9. What do you think would happen if your balloon had twice the mass when you launched it? Answer the question using Newton’s Fi
dalvyx [7]
Well that thing doesn’t obey the laws of physics at all. There’s a lot here that you won’t understand kid
8 0
3 years ago
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