All categories

2 years ago

Why does a purple flower appear purple when white light shines on it?

Physics

1 answer:

grandymaker [24]2 years ago

5 0

The flower absorbs all light but purple, making it appear, purple!

You might be interested in

If an electric circuit has 0 A of current running through it then .

Mila [183]

Answer:

voltage and zero

Explanation:

I don't know i just did the Edg question

6 0

2 years ago

The Hi line of the Balmer series is emitted in the transition from n = 3 to n = 2. Compute the wavelength of this line for l H a

irina1246 [14]

Answer:

$\lambda=550\ nm$

Explanation:

The Hi line of the Balmer series is emitted in the transition from n = 3 to n = 2 i.e. $n_i=3$ and $n_f=2$

The wavelength of Hi line of the Balmer series is given by :

$\dfrac{1}{\lambda}=R(\dfrac{1}{n_f}-\dfrac{1}{n_i})$

$\dfrac{1}{\lambda}=1.09\times 10^7\times (\dfrac{1}{2}-\dfrac{1}{3})$

$\lambda=5.50\times 10^{-7}\ m$

$\lambda=550\ nm$

So, the wavelength for this line is 550 nm. Hence, this is the required solution.

6 0

2 years ago

The earth's interior heat and pressure drive a process of heat transfer in the mantle called _____.

Galina-37 [17]

Convection. It is the transfer of heat by the circulation and movement of the molecules that come from liquid or gas.

5 0

2 years ago

Read 2 more answers

An proton-antiproton pair is produced by a 2.20 × 10 3 MeV photon. What is the kinetic energy of the antiproton if the kinetic e

timama [110]

Answer:

K = 80.75 MeV

Explanation:

To calculate the kinetic energy of the antiproton we need to use conservation of energy:

$E_{ph} = E_{p} + E_{ap} = E_{0p} + K_{p} + E_{0ap} + K_{ap} = m_{0p}c^{2} + K_{p} + m_{0ap}c^{2} + K_{ap}$

<em>where $E_{ph}$ : is the photon energy, $E_{0p} and E_{0ap}$ : are the rest energies of the proton and the antiproton, respectively, equals to m₀c², $K_{p} and K_{ap}$ : are the kinetic energies of the proton and the antiproton, respectively, c: speed of light, and m₀: rest mass.</em>

Therefore the kinetic energy of the antiproton is:

$K_{ap} = E_{ph} - m_{0p}c^{2} - K_{p} - m_{0ap}c^{2}$

<u>The proton mass is equal to the antiproton mass, so</u>:

$K_{ap} = E_{ph} - 2m_{0p}c^{2} - K_{p}$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2} - 242.85MeV$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2}(\frac{1eV}{1.602 \cdot 10^{-19}J})(\frac{1 MeV}{10^{6}eV}) - 242.85MeV$

$K_{ap} = 80.75 MeV$

Hence, the kinetic energy of the antiproton is 80.75 MeV.

I hope it helps you!

3 0

3 years ago

What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wave

Firlakuza [10]

Answer:

thinnest soap film is 206.76 nm

Explanation:

Given data

wavelength = 550 nm

index of refraction n = 1.33

to find out

What is the thinnest soap film

solution

we have wavelength λ = 550 nm

that is λ = 550 × $10^{-9}$ m

and n = 1.3

we will find the thickness of soap film as given by formula that is

thickness = λ/2n

thickness = 550 × $10^{-9}$ / 2(1.33)

thickness = 206.76 × $10^{-9}$ m

thinnest soap film is 206.76 nm

7 0

2 years ago