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-BARSIC- [3]
3 years ago
12

A shopper pushes a grocery cart 20.0 m at constant speed on level ground, against a 35.0 n frictional force. he pushes in a dire

ction 25.0? below the horizontal. what is the work done on the cart by the gravitational force?
Physics
1 answer:
alexandr1967 [171]3 years ago
5 0

Work is calculated as the product of Force, Distance, and angular motion. In this case, the work done by gravity is perpendicular to the motion of the cart, so θ = 90°

 and W=Fdcosθ

W=35.0 N x 20.0 m x cos90

W=0 J

This means that work done perpendicular to the direction of the motion is always zero.

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Holding onto a tow rope moving parallel to a frictionless ski slope, a 61.8 kg skier is pulled up the slope, which is at an angl
nata0808 [166]

Answer:

a) Frope= 71.7 N

b) Frope=6.7 N

Explanation:

In the figure the skier is simulated as an object, "a box".

a) At constant velocity we can say that the object is in equilibrium, so we apply the Newton's first law:

∑F=0

Frope=w*sen6.8°

Frope=71.71N

Take into account that w is the weight that is calculated as mass per gravitiy constant:

w=m*g

w=61.8Kg*9.8\frac{m}{s^{2} }

w=605.64N

b) In this case the system has an acceleration of 0.109m/s2.  Then, we apply Newton's second law of motion:

F=m*a

F=61.8Kg*0.109m/s2

Frope=6.73N

8 0
3 years ago
All electromagnetic waves travel in vacuum at the speed of c=3×10^8 m/s. Find the wavelength of microwaves of frequency 10^10 Hz
erica [24]
Recall the wave equation, c=f\lambda where c is the speed of the wave (m/s), f is the frequency of the wave (Hz) and λ is the wavelength of the wave (m).

c=f\lambda \Rightarrow \lambda =  \frac{c}{f} so \lambda =  \frac{3 \times 10^8}{10^{10}} = 0.03 \text{m}
5 0
3 years ago
Describe the difference between balanced forces and action/reaction forces
Alecsey [184]
 Balanced forces<span> act on the same object and </span>Action-Reaction forces<span> act on different objects.</span>
5 0
3 years ago
Read 2 more answers
The wave shown below is produced in a rope.
Kay [80]

Answer:

<h3>B) A dot vector drawn up and vector drawn down.</h3>

Explanation:

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3 years ago
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A 265 g mass attached to a horizontal spring oscillates at a frequency of 3.40 Hz . At t =0s, the mass is at x= 6.20 cm and has
lara [203]

Answer:

The phase constant is 7.25 degree  

Explanation:

given data

mass = 265 g

frequency = 3.40 Hz

time t = 0 s

x = 6.20 cm

vx = - 35.0 cm/s

solution

as phase constant is express as

y = A cosФ ..............1

here A is amplitude that is = \sqrt{(\frac{v_x}{\omega })^2+y^2 }  = \sqrt{(\frac{35}{2\times \pi  \times y})^2+6.2^2 }  =  6.25 cm

put value in equation 1

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cosФ  = 0.992

Ф = 7.25 degree  

so the phase constant is 7.25 degree  

5 0
3 years ago
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