1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
OLEGan [10]
3 years ago
14

A bus is traveling with a uniform acceleration of 2.75 meters/second2. If the initial velocity of the bus is 16.5 meters/second,

what will its velocity be after 9.00 seconds?
Physics
1 answer:
Kaylis [27]3 years ago
8 0
<span>The velocity will be 41.25 m/s2 after 9 seconds. To find velocity after a specific time period, multiply the acceleration (2.75) times the number of seconds (9) to receive 24.75 m/s, then add that to the initial velocity of 16.5 m/s. 24.75 + 16.5 = 41.25 m/s2.</span>
You might be interested in
What is the total number of atoms in the following formula? CaBr2 4 3 2 1
ololo11 [35]
Your answer is 3 ( 1 calcium atom and 2 bromine atoms)
8 0
3 years ago
A 50-kg copper block initially at 140°c is dropped into an insulated tank that contains 90 l of water at 10°c. Determine the f
xxMikexx [17]

Answer:

T_f=24.71

Explanation:

From the question we are told that:

Mass of block m=50

Temperature of block T_b =140 \textdegree C

Volume of water V= 90L

Temperature of water T_w=10 \textdegree C

Density of water \rho=1000kg/m^3

Specific heat of water C_w=4.18KJ/kg-k

Specific heat of copper C_p=0.96KJ/kg-k

 

Generally the equation for equilibrium stage is mathematically given by

mC_p(T_b-T_f)=\rho*VV*c(T_f-T_w)

50*0.96(140-T_f)=1000*90*10^-3*c_w(T_f-10)

48(140-T_f)=376.2(T_f-10)

140-T_f=7.8375(T_f-10)

140-T_f=7.8375T_f-78.375

-8.8375T_f=-218.375

T_f=\frac{-218.375}{-8.8375}

T_f=\frac{-218.375}{-8.8375}

T_f=24.71

6 0
3 years ago
When a high-mass star explodes, which of the following is left over in the center?
il63 [147K]
I would say option D, it depends on the size of the star
8 0
3 years ago
Which will ensure laboratory safety during the experiment? Check all that apply. using beaker tongs to handle the hot beaker rea
Aleks [24]

Answer: • using beaker tongs to handle the hot beaker.

• checking the beaker for chips prior to heating on the hot plate.

• Turning off the hot plate after use

Explanation:

The options that will ensure laboratory safety during the experiment will be:

• using beaker tongs to handle the hot beaker.

• checking the beaker for chips prior to heating on the hot plate.

• Turning off the hot plate after use.

We should note that the beaker tongs are simply used in the holding of the beakers that have hot liquids in them. Also, it s vital for the hot plate to be turned off after its use so as to prevent accident.

7 0
3 years ago
Read 2 more answers
7. Many medicines started out as natural products.Penicillin was originally made from _______________
larisa [96]
B.Bark of a willow tree
6 0
2 years ago
Read 2 more answers
Other questions:
  • How does wire thickness affect the power of the electromagnet?
    5·1 answer
  • The mole fraction of oxygen in dry air near sea level is 0.20948. The concentration of
    13·2 answers
  • the mass of a brick is 4 kg, find the mass of water displaced by it when completely immersed in water.​
    6·1 answer
  • Which of the following values represents an index of refraction of an actual material?
    10·1 answer
  • Please help ASAP. A 1550 kg car is initially at rest on level ground when the engine does 450 000 J of work on it. After the car
    11·1 answer
  • What is the summary for Electrons and protons​
    12·1 answer
  • When a carpet is beaten with a stick dust particles off<br> ...why
    5·1 answer
  • Which of the following is a definition of acceleration? *
    8·1 answer
  • A car slows down from 27.7 m/s <br> to 10.9 m/s in 2.37 s. <br> What is its acceleration?
    13·2 answers
  • A 248 kg object moving at 19m/s comes to stop over a distance of 38 m. What is the coefficient of kinetic friction between the s
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!